Spring集成(IntegrationFlowContext):动态注册到同一WebSocket服务器的新路径

问题描述 投票:1回答:1

我试图通过链接https://github.com/joshlong/techtips/tree/master/examples/spring-integration-4.1-websockets-example来使用JavaDsl实现spring websocket解决方案>

并且我通过使用脚踏客户端订阅了路径(即/ messages),成功地对其进行了测试。

接下来,我通过向IntegrationFlowContext注册集成流尝试了相同的事情。

[它在服务器端成功执行,但是当我尝试由脚踏客户端发出请求时,收到未找到404的异常。

在浏览日志时,我发现以前“ AbstractHandlerMapping”映射到SockJsHttpRequestHandler

,现在它映射到ResourceHttpRequestHandler

使用Spring管理的集成流程(成功)

DEBUG [http-nio-8081-exec-1] o.s.c.l.LogFormatUtils: GET "/messages/websocket", parameters={}
DEBUG [http-nio-8081-exec-1] o.s.w.s.h.AbstractHandlerMapping: Mapped to org.springframework.web.socket.sockjs.support.SockJsHttpRequestHandler@46185a1b
DEBUG [http-nio-8081-exec-1] o.s.w.s.s.s.AbstractSockJsService: Processing transport request: GET http://localhost:8081/messages/websocket
DEBUG [http-nio-8081-exec-1] o.s.w.s.FrameworkServlet: Completed 101 SWITCHING_PROTOCOLS
DEBUG [http-nio-8081-exec-1] o.s.w.s.h.LoggingWebSocketHandlerDecorator: New StandardWebSocketSession[id=e11b5ef5-d2e5-e5c7-819d-493f42f4a7c8, uri=ws://localhost:8081/messages/websocket]

并且使用IntegrationFlow上下文管理流(失败)

DEBUG [http-nio-8081-exec-1] o.s.c.l.LogFormatUtils: GET "/messages/websocket", parameters={}
DEBUG [http-nio-8081-exec-1] o.s.w.s.h.AbstractHandlerMapping: Mapped to ResourceHttpRequestHandler ["classpath:/META-INF/resources/", "classpath:/resources/", "classpath:/static/", "classpath:/public/", "/"]
DEBUG [http-nio-8081-exec-1] o.s.w.s.r.ResourceHttpRequestHandler: Resource not found
DEBUG [http-nio-8081-exec-1] o.s.w.s.FrameworkServlet: Completed 404 NOT_FOUND
DEBUG [http-nio-8081-exec-1] o.s.c.l.LogFormatUtils: "ERROR" dispatch for GET "/error", parameters={}
DEBUG [http-nio-8081-exec-1] o.s.w.s.h.AbstractHandlerMapping: Mapped to org.springframework.boot.autoconfigure.web.servlet.error.BasicErrorController#error(HttpServletRequest)
DEBUG [http-nio-8081-exec-1] o.s.w.s.m.m.a.AbstractMessageConverterMethodProcessor: Using 'application/json', given [*/*] and supported [application/json, application/*+json, application/json, application/*+json]
DEBUG [http-nio-8081-exec-1] o.s.c.l.LogFormatUtils: Writing [{timestamp=Tue Feb 25 17:06:58 IST 

我正在尝试通过以下链接使用JavaDsl来实现Spring Websocket解决方案,即https://github.com/joshlong/techtips/tree/master/examples/spring-integration-4.1-websockets-example我...] >

spring spring-boot spring-integration spring-integration-dsl
1个回答
0
投票

由于Mapped to ...中的getHandler(HttpServletRequest request)逻辑,您具有不同的AbstractHandlerMapping

Object handler = getHandlerInternal(request);
    if (handler == null) {
        handler = getDefaultHandler();
    }
    if (handler == null) {
        return null;
    }
    // Bean name or resolved handler?
    if (handler instanceof String) {
        String handlerName = (String) handler;
        handler = obtainApplicationContext().getBean(handlerName);
    }

    HandlerExecutionChain executionChain = getHandlerExecutionChain(handler, request);

    if (logger.isTraceEnabled()) {
        logger.trace("Mapped to " + handler);
    }
© www.soinside.com 2019 - 2024. All rights reserved.