在GraphQL架构中使用通用对象作为输入类型的问题错误:架构必须包含唯一的命名类型

问题描述 投票:0回答:1

我有一个插件,当用户创建标签时,会创建一个{id:“XXX”,text:“XXX”}的对象。我试图让我的apollo graphql服务器接受这个对象作为我的架构中的类型。我尝试了很多东西,但对我来说最有意义的是创建一个具有该对象形状的类型并使用它。这似乎适用于原始类型,但不适用于输入(更新和新)。我收到一个错误:错误:架构必须包含唯一的命名类型,但包含多个名为“CustomQuestionOption”的类型。

const customQuestionTypeDefs = `
type CustomQuestionOption {
  id: ID,
  text: String
}

type CustomQuestion {
  id: ID!
  question: String
  questionType: String
  options: [CustomQuestionOption]
  required: Boolean
}

input UpdatedCustomQuestion {
  id: ID!
  question: String
  questionType: String
  options: [CustomQuestionOption]
  required: Boolean
}

input NewCustomQuestion {
  question: String
  questionType: String
  options: [CustomQuestionOption]
  required: Boolean
}

extend type Query {
  CustomQuestion(id: ID!): CustomQuestion!
  allCustomQuestions: [CustomQuestion]!
}

extend type Mutation {
  newCustomQuestion(input: NewCustomQuestion!): CustomQuestion!
  updateCustomQuestion(input: UpdatedCustomQuestion!): CustomQuestion!
}
`;

export default customQuestionTypeDefs;

然后组合起来就像

const baseSchema = `
  schema {
    query: Query
    mutation: Mutation
  }
`;

export const schema = makeExecutableSchema({
  typeDefs: [baseSchema, eventTypeDefs, sponsorshipItemTypeDefs, customQuestionTypeDefs, userTypeDefs],
  resolvers: merge({}, eventResolvers, sponsorshipItemResolvers, customQuestionResolvers, userResolvers)
});

有没有办法让我的服务器在输入中接受这个对象,还是我必须保存为字符串并在保存和加载时转换它? (即“[{id:'S',text:'S'}]”)

graphql apollo-server
1个回答
1
投票

我想我想要创建的是一个自定义标量(而不是内置的字符串,如字符串,int等)。我将customQuestionOption更改为标量是我需要做的。编辑 - 见下文

const customQuestionTypeDefs = `
scalar CustomQuestionOption {
  id: String,
  text: String
}

type CustomQuestion {
  id: ID!
  question: String
  questionType: String
  options: [CustomQuestionOption]
  required: Boolean
}

input UpdatedCustomQuestion {
  id: ID!
  question: String
  questionType: String
  options: [CustomQuestionOption]
  required: Boolean
}

input NewCustomQuestion {
  question: String
  questionType: String
  options: [CustomQuestionOption]
  required: Boolean
}

extend type Query {
  CustomQuestion(id: ID!): CustomQuestion!
  allCustomQuestions: [CustomQuestion]!
}

extend type Mutation {
  newCustomQuestion(input: NewCustomQuestion!): CustomQuestion!
  updateCustomQuestion(input: UpdatedCustomQuestion!): CustomQuestion!
}
`;

export default customQuestionTypeDefs;

除了无法查询对象的各个属性外,此方法工作正常。真正的解决方案是将CustomQuestionOption转回到在查询中使用的类型,并创建另一个输入(我称之为InputCustomQuestionOption)并将其用于最终输入:

const customQuestionTypeDefs = `
type CustomQuestionOption {
  id: String,
  text: String
}

input InputCustomQuestionOption {
  id: String,
  text: String
}

type CustomQuestion {
  id: ID!
  question: String
  questionType: String
  options: [CustomQuestionOption]
  required: Boolean
}

input UpdatedCustomQuestion {
  id: ID!
  question: String
  questionType: String
  options: [InputCustomQuestionOption]
  required: Boolean
}

input NewCustomQuestion {
  question: String
  questionType: String
  options: [InputCustomQuestionOption]
  required: Boolean
}
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