django SearchFilter在搜索字段为空时显示所有数据？

Question

我已经使用django SearchFilter DRF实现了搜索功能，该功能可以正常工作，但问题是当我在搜索字段中未传递任何内容时，我不想显示所有查询。默认情况下，返回所有查询。我不不知道如何处理，这是我的代码 views.py

    class EventSearchView(generics.ListAPIView):
          permission_classes = (AllowAny,)
          queryset = Event.objects.all()
          search_fields = ["name", "description","content"]
          filter_backends = (filters.SearchFilter,)
          serializer_class = EventSearchSerializer
          pagination_class = LargeResultsSetPagination

when i search for fields "name", "description" it is working fine but when i search nothing and hit the url without search fields by default it is returning all the query , but i want to display nothing , how will i achieve that, any help would be appreciated

Answer 1

尝试覆盖get_queryset方法以检查query_params是否包含数据：

class EventSearchView(generics.ListAPIView):
    permission_classes = (AllowAny,)    
    search_fields = ["name", "description","content"]
    filter_backends = (filters.SearchFilter,)
    serializer_class = EventSearchSerializer
    pagination_class = LargeResultsSetPagination

    def get_queryset(self):
        if self.request.query_params:    
            return Event.objects.all()
    return Event.objects.none()

Answer 2

另一种方式是使用Filter类。只需在任何地方定义它即可。

from django_filters import rest_framework as filters

class ContentFilter(filters.FilterSet):
    name = filters.CharFilter(required=True)

    class Meta:
    model = <your_model>
    fields = ['name']

比起您可以在视图中添加它：

filterset_class = ContentFilter

现在将需要您的name参数，没有它，没有人可以获取您的请求。这是更好的方法，因为如果用户忘记发送参数，他会收到错误消息，而不是空白的响应。