bash脚本中的grep和mysql变量

Question

我有一个带有此变量的bash脚本，然后在for中使用它来复制每个服务器数据库：

bdtocopy = $ (mysql -Ns -uadmin -p`cat / etc / psa / .psa.shadow` -e "SHOW DATABASES" | grep -Ev "^ (horde | apsc | psa | mysql | phpmyadmin_ne2tX0wklnQh | performance_schema | information_schema) $ ")`

我想将其分开，但对我不起作用：

[

bdtoexclude = $ (horde | apsc | psa | mysql | phpmyadmin_ne2tX0wklnQh | performance_schema | information_schema)
databases = $ (mysql -Ns -uadmin -p

cat / etc / psa / .psa.shadow

-e "SHOW DATABASES")
bdtocopy = $ (echo $ databases | grep -Ev "$ bdtoexclude")

怎么办？

Answer 1

pass="$(</etc/psa/.psa.shadow)"
databases="$(mysql -Ns -uadmin -p${pass} -e 'SHOW DATABASES')"
bdtoexclude='^(horde|apsc|psa|mysql|phpmyadmin_ne2tX0wklnQh|performance_schema|information_schema)$'
bdtocopy="$(grep -Ev "${bdtoexclude}" <<< "${databases}")"