是否可以在pyspark中编写自引用列

问题描述 投票:0回答:1

我正在写一个小poc,试图将用python编写的一段逻辑重写到pyspark,其中我一一处理存储在sqlite中的日志:

logs = [...]
processed_logs = []
previous_log = EmptyDecoratedLog() #empty
for log in logs:
    processed_log = with_outlet_value_closed(log, previous_log)
    previous_log = processed_log 
    processed_logs.append(processed_log)

def with_outlet_value_closed(current_entry: DecoratedLog, previous_entry: DecoratedLog):
    if current_entry.sourceName == "GS2":
        self.outletValveClosed = current_entry.eventData
    else:
        self.outletValveClosed = previous_entry.outletValveClosed

我想在 pyspark api 中表示为:

import pyspark.sql.functions as f
window = W.orderBy("ID") #where ID is unique id on those logs
df.withColumn("testValveOpened",
                f.when((f.col("sourceName") == "GS2"), f.col("eventData"))
                .otherwise(f.lag("testValveOpened").over(window)),
                )

但这会导致 AnalysisException: [UNRESOLVED_COLUMN.WITH_SUGGESTION] 无法解析名称为

outletValveClosed
的列或函数参数。

所以我的问题是: 是否可以表示这样的代码,其中当前行的值取决于同一列的前一行(我知道这将导致所有记录在单个线程上处理,但这很好)

我尝试添加列的初始化

df = df.withColumn("testValveOpened", f.lit(0))
df.withColumn("testValveOpened",
                f.when((f.col("sourceName") == "GS2"), f.col("eventData"))
                .otherwise(f.lag("testValveOpened").over(window)),
                )

但后来我得到了

ID |sourceName|eventData|testValveOpened
1  |GS3       |1        |0
2  |GS2       |1        |1
3  |GS2       |1        |1
4  |GS1       |1        |0
5  |GS1       |1        |0
6  |ABC       |0        |0
7  |B123      |0        |0
8  |B423      |0        |0
9  |PTSD      |168      |0
10 |XCD       |0        |0

我想得到

ID |sourceName|eventData|testValveOpened
1  |GS3       |1        |0
2  |GS2       |1        |1
3  |GS2       |1        |1
4  |GS1       |1        |1
5  |GS1       |1        |1
6  |ABC       |0        |1
7  |B123      |0        |1
8  |B423      |0        |1
9  |PTSD      |168      |1
10 |XCD       |0        |1  

因此,当有 GS2 时,取 eventData 的值,否则取之前 testValueOpened 的 cary 值

python pyspark lag
1个回答
0
投票

您必须稍微重写逻辑,因为您无法“逐一”更新每一行。首先检查 HS2:

df.withColumn("testValveOpened", f.when(f.col("sourceName" == "GS2"), f.lit(1)).otherwise(0))

然后进行累计和比较,看看之前是否存在 GS2:

df.withColumn("testValveOpened", f.sum("testValveOpened").over(window) > 1)
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