超越自定义例外，但显示所有其他例外

Question

我正在运行以下尝试代码：

try:
    paths = file_system_client.get_paths("{0}/{1}/0/{2}/{3}/{4}".format(container_initial_folder, container_second_folder, chronological_date[0], chronological_date[1], chronological_date[2]), recursive=True)
    list_of_paths=["abfss://{0}@{1}.dfs.core.windows.net/".format(storage_container_name, storage_account_name)+path.name for path in paths if ".avro" in path.name]

except Exception as e:
    if e=="AccountIsDisabled":
        pass
    else:
        print(e)

如果尝试失败，我既不想打印以下错误，如果遇到此错误，我既不想停止程序执行，也可以：

"(AccountIsDisabled) The specified account is disabled.
RequestId:3159a59e-d01f-0091-5f71-2ff884000000
Time:2020-05-21T13:09:03.3540242Z"

我只想天桥它和打印将会发生的任何其他错误/异常（例如TypeError，ValueError等）。

在Python 3中可行吗？

请注意.get_paths（）方法属于azure.storage.filedatalake模块，该模块支持将Python与Azure Data Lake直接连接以进行路径提取。

我提供的注释是要确定我要绕过的异常不是内置的异常。

---

[[Update]在按照提出的附加答案进行排序后，我将代码修改为：

class AccountIsDisabled(Exception):
    pass

def create_list_paths(chronological_date, 
                      container_initial_folder="name1", 
                      container_second_folder="name2", 
                      storage_container_name="name3", 
                      storage_account_name="mame4"
                      ):

    list_of_paths=list()

    paths = file_system_client.get_paths("{0}/{1}/0/{2}/{3}/{4}".format(container_initial_folder, container_second_folder, chronological_date[0], chronological_date[1], chronological_date[2]), recursive=True)
    list_of_paths=["abfss://{0}@{1}.dfs.core.windows.net/".format(storage_container_name, storage_account_name)+path.name for path in paths if ".avro" in path.name]
    list_of_paths=functools.reduce(operator.iconcat, result, [])

    return list_of_paths

try:
    raise AccountIsDisabled
    list_of_paths=None
    executor=ThreadPoolExecutor(max_workers=8)
    list_of_paths=[executor.submit(create_list_paths, i, container_initial_folder, container_second_folder, storage_container_name, storage_account_name).result() for i in date_list]
    assert len(list_of_paths)!=0 #an assertion error

except AccountIsDisabled:
    pass

except (ValueError, TypeError, ArithmeticError, AssertionError, AttributeError) as e:
    print(e)

我已添加一个AssertionError，但未捕获。为什么会这样呢？另外，如果我省略raise AccountIsDisabled

我得到以下“ StorageErrorException”，它不被识别为内置异常。实际上，“ StorageErrorException”是我想超越的自定义异常，但它似乎是Python的已知异常。

"StorageErrorException: (AccountIsDisabled) The specified account is disabled.
RequestId:9463114d-701f-0088-1a78-2f783f000000
Time:2020-05-21T14:03:40.3277133Z" 

如果我执行此操作：

try:
    list_of_paths=None
    executor=ThreadPoolExecutor(max_workers=8)
    list_of_paths=[executor.submit(create_list_paths, i, container_initial_folder, container_second_folder, storage_container_name, storage_account_name).result() for i in date_list]
    assert len(list_of_paths)>0

except StorageErrorException:
    pass

except (ValueError, TypeError, ArithmeticError, AssertionError, AttributeError) as e:
    print(e)

我仍然收到StorageErrorException

Answer 1

列出[Python 3.Docs]: Compound statements - The try statement。

有几种方法可以实现这一目标。这是一个：

try:
    # ...
except StorageErrorException:
    pass
except:
    print(sys.exc_info()[1])

请注意，except:是棘手的，因为您可能会默默地处理不应该处理的异常。另一种方法是捕获代码可能显式引发的任何异常。

try:
    # ...
except StorageErrorException:
    pass
except (SomeException, SomeOtherException, SomeOtherOtherException) as e:
    print(e)

浏览[MS.Docs]: filedatalake package和源代码显示，StorageErrorException是您需要处理的代码。

可能想检查[SO]: About catching ANY exception。

Answer 2

您想比较异常的type，将条件更改为：

if type(e)==AccountIsDisabled:

示例：

class AccountIsDisabled(Exception):
    pass

print("try #1")
try:
    raise AccountIsDisabled
except Exception as e:
    if type(e)==AccountIsDisabled:
        pass
    else:
        print(e)

print("try #2")
try:
    raise Exception('hi', 'there')
except Exception as e:
    if type(e)==AccountIsDisabled:
        pass
    else:
        print(e)

输出：

try #1
try #2
('hi', 'there')