是否可以像这样一次添加许多列?
t=table(1..6 as id,(today()-5)..today() as tm);
update t set feature_1001..feature1030=float(),feature_2001..feature2020=float()
我写了以下方法,可以实现,但是感觉有点复杂。有没有更简单的方法?
for(x in 1001 .. 1030) t["feature_"+x] = float()
for(x in 2001 .. 2030) t["feature_"+x] = float()
t["feature" + string(1001 .. 1030 join 2001 .. 2030)] = loop(x->float(), 1..60)