dplyr代码工作，现在不是，我不知道为什么

Question

我在一周前编写了一些代码，这些代码效果很好，但现在它已经停止工作了。我已经更新了tidyverse包，看看这可能是问题，但事实并非如此。

以下是一些示例数据：

     yearmo    sex      eco       ue  fs12ago fs12ahead purchases
      200301   Male  neutral negative negative   neutral   neutral
      200301 Female negative negative negative   neutral   neutral
      200301 Female negative negative  neutral   neutral  positive
      200301   Male  neutral  neutral  neutral   neutral   neutral
      200301   Male negative negative negative  positive  negative
      200301   Male negative negative  neutral   neutral  positive
      200301   Male negative negative  neutral   neutral   neutral
      200301   Male negative negative positive   neutral  negative
      200301 Female negative negative negative   neutral  positive
      200301 Female negative negative positive  negative   neutral
      200301 Female negative negative negative  negative  negative
      200301 Female negative  neutral negative   neutral  negative
      200301   Male negative negative  neutral   neutral  negative
      200301 Female positive  neutral  neutral   neutral  positive
      200301   Male negative negative  neutral   neutral  positive
      200301   Male  neutral negative negative   neutral   neutral
      200301 Female  neutral negative negative   neutral   neutral
      200301   Male  neutral negative  neutral   neutral  positive
      200301 Female negative negative negative  negative  positive
      200301 Female positive negative  neutral   neutral  positive

正在运行的代码，但现在不是，这是：

    tmp_eco <- data %>% 
      group_by(yearmo) %>%
      count(yearmo, eco)

我以前获得的输出是对于称为“eco”的变量响应为正，负或中性的人数，例如：

     yearmo     eco         n
      200301  positive     10    
      200301  negative     13
      200301  neutral      9
      200301  positive     7
      200301  negative     5
      200301  neutral      16

我现在得到的错误是：

    Error: Can't subset with `[` using an object of class quoted.
    Call `rlang::last_error()` to see a backtrace

这给了我：

    <error>
    message: Can't subset with `[` using an object of class quoted.
    class:   `rlang_error`
    backtrace:
      1. dplyr::group_by(., yearmo)
      9. plyr::count(., yearmo, eco)
     14. plyr::eval.quoted(vars, df)
     18. tibble:::`[.tbl_df`(envir, exprs)
     19. tibble:::check_names_df(i, x)
    Call `rlang::last_trace()` to see the full backtrace

有关为什么会发生这种情况的任何想法？

Answer 1

随着'数据'显示，如果我们使用group_by，则不需要count

library(dplyr)
data %>% 
   dplyr::count(yearmo, eco)
# A tibble: 3 x 3
#  yearmo eco          n
#   <int> <chr>    <int>
#1 200301 negative    13
#2 200301 neutral      5
#3 200301 positive     2

data

data <- structure(list(yearmo = c(200301L, 200301L, 200301L, 200301L, 
200301L, 200301L, 200301L, 200301L, 200301L, 200301L, 200301L, 
200301L, 200301L, 200301L, 200301L, 200301L, 200301L, 200301L, 
200301L, 200301L), sex = c("Male", "Female", "Female", "Male", 
"Male", "Male", "Male", "Male", "Female", "Female", "Female", 
"Female", "Male", "Female", "Male", "Male", "Female", "Male", 
"Female", "Female"), eco = c("neutral", "negative", "negative", 
"neutral", "negative", "negative", "negative", "negative", "negative", 
"negative", "negative", "negative", "negative", "positive", "negative", 
"neutral", "neutral", "neutral", "negative", "positive"), ue = c("negative", 
"negative", "negative", "neutral", "negative", "negative", "negative", 
"negative", "negative", "negative", "negative", "neutral", "negative", 
"neutral", "negative", "negative", "negative", "negative", "negative", 
"negative"), fs12ago = c("negative", "negative", "neutral", "neutral", 
"negative", "neutral", "neutral", "positive", "negative", "positive", 
"negative", "negative", "neutral", "neutral", "neutral", "negative", 
"negative", "neutral", "negative", "neutral"), fs12ahead = c("neutral", 
"neutral", "neutral", "neutral", "positive", "neutral", "neutral", 
"neutral", "neutral", "negative", "negative", "neutral", "neutral", 
"neutral", "neutral", "neutral", "neutral", "neutral", "negative", 
"neutral"), purchases = c("neutral", "neutral", "positive", "neutral", 
"negative", "positive", "neutral", "negative", "positive", "neutral", 
"negative", "negative", "negative", "positive", "positive", "neutral", 
"neutral", "positive", "positive", "positive")), 
class = "data.frame", row.names = c(NA, 
-20L))