首次运行后,使用Runnable递归链接ConstraintLayout转换

问题描述 投票:0回答:1

我正在尝试为自定义菜单创建切换动画。有多个菜单可以通过不同的按钮选择。没有菜单打开时,点击按钮应打开该菜单。如果打开另一个菜单,则打开一个菜单,在该动画之后,应打开所选菜单。每个结束/打开操作都与ConstraintLayout转换相结合。

由于它无法正常工作,我创建了以下测试程序:

@Override
protected void onCreate(Bundle savedInstanceState) {
    ...
    ConstraintLayout layout_main;
    ConstraintSet l_mh0c = new ConstraintSet();
    ConstraintSet l_mh1o = new ConstraintSet();
    ConstraintSet l_mh1c = new ConstraintSet();

    Button btn;
    btn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            toggleOne();
        }
    });
    layout_main = (ConstraintLayout) findViewById(R.id.constraintMain);
    l_mh1o.clone(this, R.layout.main_menue_header1_open);
    l_mh1c.clone(this, R.layout.main_menue_header1_closed);
    l_mh0c.clone(this, R.layout.activity_main);
    ...
}

int openedMenue = -1;
long animationTime = 1000;
private void toggleOne() {
    TransitionManager.endTransitions(layout_main); //<- makes no difference when commented
    if(openedMenue==1) {              
        System.out.println("sync closing");
        Runnable r = () -> toggleOne();
        closeMenue(1, animationTime, r);
    } else {
        System.out.println("sync opening");
        startMenue(1, animationTime);
    }
}

public void startMenue(Integer index, final Long maxtime) {
    Transition t;
    switch (index) {
        case 1:
            t = new ChangeBounds();
            t.setDuration(0).addListener(new TransitionEndListener() {
                @Override
                public void onTransitionEnd(Transition transition) {
                    Transition t = new ChangeBounds();
                    t.setDuration(maxtime / 2).addListener(new TransitionEndListener() {
                        @Override
                        public void onTransitionEnd(Transition transition) {
                            Transition t = new ChangeBounds();
                            t.setDuration(maxtime / 2);
                            TransitionManager.beginDelayedTransition(layout_main, t);
                            l_mh0o.applyTo(layout_main);
                            openedMenue = 1;
                            System.out.println("sync start finished");
                        }
                    });
                    TransitionManager.beginDelayedTransition(layout_main, t);
                    l_mh1o.applyTo(layout_main);

                }
            });
            TransitionManager.beginDelayedTransition(layout_main, t);
            l_mh1c.applyTo(layout_main);
            // the following does not provoke any changes
            Scene s = new Scene(layout_main); 
            TransitionManager.go(s);
            break;
    }
}

private void closeMenue(int index, final long maxtime, Runnable callback) {
    System.out.println("sync closing menue " + openedMenue);
    Transition t;
    switch (index) {
        case 1:
            t = new ChangeBounds();
            t.setDuration(maxtime/2).addListener(new TransitionEndListener() {
                @Override
                public void onTransitionEnd(Transition transition) {
                    Transition t = new ChangeBounds();
                    t.setDuration(maxtime/2).addListener(new TransitionEndListener() {
                        @Override
                        public void onTransitionEnd(Transition transition) {
                            Transition t = new ChangeBounds();
                            t.setDuration(0);
                            TransitionManager.beginDelayedTransition(layout_main, t);
                            l_mh0c.applyTo(layout_main);
                            openedMenue = -1;
                            try {
                                callback.run();
                            } catch (Exception e) { e.printStackTrace(); }
                        }
                    });
                    TransitionManager.beginDelayedTransition(layout_main, t);
                    l_mh1c.applyTo(layout_main);
                    openedMenue = 1;
                }
            });
            TransitionManager.beginDelayedTransition(layout_main, t);
            l_mh1o.applyTo(layout_main);
            break;
    }
}

当我运行它时,我得到以下输出:

[Button Click]
sync opening
sync start finished
[Button Click]
sync closing
sync closing menue 1
sync opening
sync start finished // problem

但是,最后一行从未打印过;似乎(在关闭操作再次开始打开操作之后)startMenue()中的第一个转换从不对onTransitionEnd()进行回调。

这是TransitionEndListener(只是一个简单的接口包装器)

public abstract class TransitionEndListener implements Transition.TransitionListener {

    @Override
    public final void onTransitionStart(Transition transition) {}

    @Override
    public final void onTransitionCancel(Transition transition) {}

    @Override
    public final void onTransitionPause(Transition transition) {}

    @Override
    public final void onTransitionResume(Transition transition) {}
}

我已经检查了是否通过在onTransitionCancel()中放置一个print语句来取消第二个启动Transition,这似乎不是这种情况。

你能解释一下为什么会这样吗?

UPDATE

我找到了this post on TransitionManager callbacks;

从mh0c t0 mh1c的转换是ConstraintLayout转换,因为约束实际上发生了变化;但是,转换在UI上不可见,因为转换中元素的宽度为0.(此转换是从一个菜单点跳转到另一个不应该可见的菜单点。)

这可能是Transition不进行回调的原因吗?

如果是这样;我怎么能绕过这个?

更新2我正在阅读the documentation,可能已经找到了使用TransitionManager.go(scene, transition)的解决方案。

- >不幸的是这没用;请参阅startMenue()代码以了解更改

android runnable android-constraintlayout android-transitions
1个回答
0
投票

经过越来越多的努力和审查这些帖子:

我发现是什么造成了麻烦:

在closeMenue()的最内部(最内部回调)

Transition t = new ChangeBounds();
t.setDuration(0);
TransitionManager.beginDelayedTransition(layout_main, t);
l_mh0c.applyTo(layout_main);
openedMenue = -1;
try {
     callback.run();
} catch (Exception e) { e.printStackTrace(); }

命令序列略有错误。它应该如下所示:

Transition t = new ChangeBounds();
t.setDuration(0).addListener(new TransitionEndListener() {
    @Override
    public void onTransitionEnd(Transition transition) {
        try {
            callback.run();
        } catch (Exception e) { e.prtinStackTrace(); }
    }
});
TransitionManager.beginDelayedTransition(layout_main, t);
l_mh0c.applyTo(layout_main);
openedMenue = -1;

这确保首先完成关闭过渡,然后开始开始转换。

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