Java的箭头函数作为函数参数不能被推断为Function或Consumer

Question

这里是Test.java的代码：

import java.util.function.Consumer;
import java.util.function.Function;

public class Test{
    private static void test(Function function){
        System.out.println("function");
    }
    private static void test(Consumer consumer){
        System.out.println("consumer");
    }

    public static void main(String[] args) {
        /// arrow1: no error
        test(i-> {System.out.println();});
        /// arrow2: no error
        test((Object i)-> System.out.println());
        /// arrow3: error: reference to test is ambiguous
        test(i-> System.out.println());
        /// arrow4: error: incompatible types: bad return type in lambda expression
        Function function = i-> System.out.println();
    }
}

Arrow3 推断箭头函数不是右函数，但 arrow4 可以。

---

arrow3: javac Test.java

Test.java:18: error: reference to test is ambiguous
        test(i-> System.out.println());
        ^
  both method test(Function) in Test and method test(Consumer) in Test match
Test.java:18: error: incompatible types: bad return type in lambda expression
        test(i-> System.out.println());
                                   ^
    void cannot be converted to Object
Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output
2 errors

arrow4: javac Test.java

Test.java:20: error: incompatible types: bad return type in lambda expression
        Function function = i-> System.out.println();
                                                  ^
    void cannot be converted to Object
1 error

我是Java新手，问过同事和ChatGPT，都没有得到满意的答复。我想知道是Java的BUG还是我不懂Java的语法，谢谢！