我的目的不是打开和显示 FatalException
错误。我要求浏览器打开链接,但无法打开,找不到这个 error
.
public void searchQuestion(View view) {
String queryString = search_input.getText().toString();
Log.d(TAG, "searchQuestion: "+ search_input.getText());
Uri buildURI = Uri.parse(BASE_URL).buildUpon()
.appendQueryParameter(QUERY_PARM, queryString)
.build();
Log.d("buildURI", "getBookInfo: " + buildURI);
Uri uri = Uri.parse(String.valueOf(buildURI));
Intent intent = new Intent(Intent.ACTION_WEB_SEARCH, uri);
startActivity(intent);
}
使用 ACTION_VIEW
而不是 ACTION_WEB_SEARCH
.
Uri uri = Uri.parse(String.valueOf(buildURI));
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);
更多信息 https:/developer.android.comreferenceandroidcontentIntent#ACTION_WEB_SEARCH。