R - 如何根据第一行中的值组合数据框中的列

问题描述 投票:1回答:1

我有这个数据框(参见下面的dput),其中有不同的列,每个列在第一行都有一个标识符/名称。我想将第一行中具有相同值的所有列组合到一列。因此,最终结果将是具有十二个列(第一行中的唯一值)的数据帧,其中包含行1中具有相同名称的所有值。

我尝试了group_by以及聚集,但两者都不是我想要的。

structure(list(V1 = structure(c(13L, 10L, 2L, 12L, 1L, 6L, 11L, 
7L, 8L, 5L, 4L, 3L, 9L), .Label = c("146", "173", "213", "422", 
"44,75", "528", "538", "558", "585", "61,41", "656", "90,8", 
"A. fumigatus"), class = "factor"), V2 = structure(c(13L, 3L, 
10L, 11L, 12L, 7L, 8L, 4L, 6L, 5L, 9L, 1L, 2L), .Label = c("129", 
"141", "15,42", "153", "16,33", "171", "177", "306", "374", "42,69", 
"80,58", "89,28", "A. fumigatus"), class = "factor"), V3 = structure(c(13L, 
8L, 1L, 5L, 6L, 2L, 4L, 11L, 10L, 12L, 3L, 9L, 7L), .Label = c("11,93", 
"115", "159", "164", "22,83", "22,84", "39,84", "4,27", "43,91", 
"53,33", "54,78", "6,75", "A. fumigatus"), class = "factor"), 
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    5L, 5L, 5L), .Label = c("10000", "1930", "5238", "A. fumigatus", 
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    6L, 6L, 6L, 6L, 6L, 3L, 6L, 6L, 6L), .Label = c("4315", "4324", 
    "7650", "7842", "A. fumigatus", "NaN"), class = "factor"), 
    V6 = structure(c(5L, 2L, 3L, 4L, 6L, 6L, 6L, 6L, 6L, 1L, 
    6L, 6L, 6L), .Label = c("28,52", "3,20", "380", "399", "A. fumigatus", 
    "NaN"), class = "factor"), V7 = structure(c(13L, 12L, 9L, 
    11L, 6L, 2L, 5L, 1L, 3L, 4L, 8L, 10L, 7L), .Label = c("1088", 
    "1281", "1327", "167", "1897", "1985", "2143", "2467", "654", 
    "664", "806", "97,88", "A. fumigatus"), class = "factor"), 
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    "NaN"), class = "factor"), V33 = structure(c(4L, 2L, 1L, 
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    V104 = structure(c(6L, 1L, 4L, 2L, 5L, 5L, 5L, 5L, 5L, 3L, 
    5L, 5L, 5L), .Label = c("1123", "699", "79,96", "8006", "NaN", 
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    V106 = structure(c(13L, 3L, 2L, 11L, 10L, 4L, 12L, 8L, 1L, 
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    "2079", "3960", "4168", "4974", "609", "7635", "7766", "NaN", 
    "S. aureus"), class = "factor"), V108 = structure(c(10L, 
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-13L))

谢谢你的时间。

r dataframe grouping tidyverse
1个回答
1
投票
# set first values as column names
names(df) <- as.character(unlist(df[1,]))
# remove first values
df <- df[-1,]
# convert all columns to numeric (convert to character and remove commas first)
df[] <- lapply(df, function(x) as.numeric(gsub(',', '', x)))
# combine same-name columns to create new data frame
df2 <- as.data.frame(lapply(split.default(df, names(df)), unlist))
rownames(df2) <- NULL
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