插入后如何在datagridview中立即刷新或显示?

问题描述 投票:13回答:7

将数据输入所有文本框后,单击提交按钮后,它不会立即显示在datagridview中,我需要重新打开表单才能看到新插入的行。要刷新什么代码?

跟着@ user3222297代码。通过添加grdPatient.Update();和grdPatient.Refresh();单击确定插入成功后仍然无法刷新。

     using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Data.SqlClient;
using System.Configuration;

namespace GRP_02_03_SACP
{
    public partial class patient : Form
    {
        // Data Table to store employee data
        DataTable Patient = new DataTable();

        // Keeps track of which row in Gridview
        // is selected
        DataGridViewRow currentRow = null;

        SqlDataAdapter PatientAdapter;

        public patient()
        {
            InitializeComponent();
        }

        private void btnSubmit_Click(object sender, EventArgs e)
        {
            if (btnSubmit.Text == "Clear")
            {
                btnSubmit.Text = "Submit";

                txtpFirstName.Focus();
            }
            else
            {
               btnSubmit.Text = "Clear";
            int result = AddPatientRecord();
            if (result > 0)
            {
                MessageBox.Show("Insert Successful");
                grdPatient.Update(); 
                grdPatient.Refresh();
            }
            else
                MessageBox.Show("Insert Fail");

            }
        }
        private int AddPatientRecord()
        {
            int result = 0;
            // TO DO: Codes to insert customer record
            //retrieve connection information info from App.config
            string strConnectionString = ConfigurationManager.ConnectionStrings["sacpConnection"].ConnectionString;
            //STEP 1: Create connection
            SqlConnection myConnect = new SqlConnection(strConnectionString);
            //STEP 2: Create command
            String strCommandText = "INSERT PATIENT(pFirstName, pLastName, pContact, pAddress, pCity, pZip, pNationality, pRace, pIC, pGender, pDOB, pBloodType, pEmail) "
                + " VALUES (@pFirstName,@pLastName,@pContact,@pAddress,@pCity,@pZip,@pNationality, @pRace, @pIC, @pGender, @pDOB, @pBloodType, @pEmail)";

            SqlCommand updateCmd = new SqlCommand(strCommandText, myConnect);

            updateCmd.Parameters.AddWithValue("@pFirstName", txtpFirstName.Text);
            updateCmd.Parameters.AddWithValue("@pLastName", txtpLastName.Text);
            //updateCmd.Parameters["@clientid"].Direction = ParameterDirection.Output; 
            updateCmd.Parameters.AddWithValue("@pContact", txtpContact.Text);
            updateCmd.Parameters.AddWithValue("@pAddress", txtpAddress.Text);
            updateCmd.Parameters.AddWithValue("@pCity", txtpCity.Text);
            updateCmd.Parameters.AddWithValue("@pZip", txtpZip.Text);
            updateCmd.Parameters.AddWithValue("@pNationality", txtpNationality.Text);
            updateCmd.Parameters.AddWithValue("@pRace", txtpRace.Text);
            updateCmd.Parameters.AddWithValue("@pIC", txtpIC.Text);
            updateCmd.Parameters.AddWithValue("@pGender", txtpGender.Text);
            updateCmd.Parameters.AddWithValue("@pDOB", txtpDOB.Text);
            updateCmd.Parameters.AddWithValue("@pBloodType", txtpBloodType.Text);
            updateCmd.Parameters.AddWithValue("@pEmail", txtpEmail.Text);
            // STEP 3 open connection and retrieve data by calling ExecuteReader
            myConnect.Open();
            // STEP 4: execute command
            // indicates number of record updated.
            result = updateCmd.ExecuteNonQuery();

            // STEP 5: Close
            myConnect.Close();
            return result;

        }

        private void patient_Load(object sender, EventArgs e)
        {
            LoadPatientRecords();
        }

        private void LoadPatientRecords()
        {

            //retrieve connection information info from App.config
            string strConnectionString = ConfigurationManager.ConnectionStrings["sacpConnection"].ConnectionString;
            //STEP 1: Create connection
            SqlConnection myConnect = new SqlConnection(strConnectionString);
            //STEP 2: Create command
            string strCommandText = "SELECT pFirstName, pLastName, pContact, pAddress, pCity, pZip, pNationality, pRace, pIC, pGender, pDOB, pBloodType, pEmail, pUsername, pPassword FROM Patient";

            PatientAdapter = new SqlDataAdapter(strCommandText, myConnect);

            //command builder generates Select, update, delete and insert SQL
            // statements for MedicalCentreAdapter
            SqlCommandBuilder cmdBuilder = new SqlCommandBuilder(PatientAdapter);
            // Empty Employee Table first
            Patient.Clear();
            // Fill Employee Table with data retrieved by data adapter
            // using SELECT statement
            PatientAdapter.Fill(Patient);

            // if there are records, bind to Grid view & display
            if (Patient.Rows.Count > 0)
                grdPatient.DataSource = Patient;
        }
    }
}
c# button datagridview insert refresh
7个回答
4
投票

成功插入后使用LoadPatientRecords()

请尝试以下代码

private void btnSubmit_Click(object sender, EventArgs e)
{
        if (btnSubmit.Text == "Clear")
        {
            btnSubmit.Text = "Submit";

            txtpFirstName.Focus();
        }
        else
        {
           btnSubmit.Text = "Clear";
           int result = AddPatientRecord();
           if (result > 0)
           {
               MessageBox.Show("Insert Successful");

               LoadPatientRecords();
           }
           else
               MessageBox.Show("Insert Fail");
         }
}

9
投票

只需要像这样再次填充datagrid:

this.XXXTableAdapter.Fill(this.DataSet.XXX);

如果您使用从dataGridView自动连接此代码在Form_Load()中自动创建


4
投票

尝试在每次插入后刷新datagrid

datagridview1.update();
datagridview1.refresh();  

希望这对你有所帮助!


3
投票

你可以将qazxsw poi qazxsw poi设置为qazxsw poi并再次绑定它。

datagridview

0
投票

我不知道你是否解决了你的问题,但解决这个问题的一个简单方法是重建datagridview的DataSource(它是一个属性)。例如:

DataSource

因此,在该MethodThatReturnList()中,您可以构建一个List(List是一个类),其中包含您需要的所有项目。在我的例子中,我有一个方法返回我在datagridview上的两列的值。

PASCH。


0
投票

在表单设计器中使用工具箱添加新计时器。在属性中将“已启用”设置为“True”。

null

private void button1_Click(object sender, EventArgs e) { myAccesscon.ConnectionString = connectionString; dataGridView.DataSource = null; dataGridView.Update(); dataGridView.Refresh(); OleDbCommand cmd = new OleDbCommand(sql, myAccesscon); myAccesscon.Open(); cmd.CommandType = CommandType.Text; OleDbDataAdapter da = new OleDbDataAdapter(cmd); DataTable bookings = new DataTable(); da.Fill(bookings); dataGridView.DataSource = bookings; myAccesscon.Close(); } 设置为等于计时器中的新数据

grdPatient.DataSource = MethodThatReturnList();


0
投票

尝试下面的代码。

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