如何加载基于文本的程序时播放mp3文件？ Python

Question

所以我正在使用输入和if语句制作基于文本的python文件。但是如何在输入加载时播放mp3文件？我正在使用Ubuntu btw

我已经尝试过pyglet，winsound，os，但它们都不起作用我尝试了pygame，但是在加载输入时无法播放文件

---

print("Welcome user")
name = input("Client name: ")
gender = input("Mr or Miss: ")
age = input("Client age: ")
room = input("Room: ")
sure = input("""All done!!!
Press any key to show the view!""")

welcome = f"""Welcome to room {room} {gender}. {name}!
Have a nice stay"""

if sure == "a":
    print(welcome)
else:
    print(welcome)

---

Os - "Module os has no startfile member"

pyglet - Doesnt import

winsound - Doesn't play the file

---

唯一成功播放mp3文件的尝试是当我使用pygame时，但即使那样，它也不会同时加载输入无论如何，这是代码：

import pygame
import time
pygame.init()

pygame.mixer.music.load("elevmusic.mp3")

pygame.mixer.music.play()

time.sleep(10)

print("Welcome user")
name = input("Client name: ")
gender = input("Mr or Miss: ")
age = input("Client age: ")
room = input("Room: ")
sure = input("""All done!!!
Press any key to show the view!""")

welcome = f"""Welcome to room {room} {gender}. {name}!
Have a nice stay"""

if sure == "a":
    print(welcome)
else:
    print(welcome)

Answer 1

以下代码对我有用：

但是您发布的代码几乎没有变化。

我正在使用python 3.6和pygame 1.9.6在Linux上运行。

如果不起作用，请指定操作系统，python版本和pygame版本。

import pygame

pygame.init()

pygame.mixer.music.load("elevmusic.mp3")
print("loaded")

pygame.mixer.music.play()
print("started play")

print("Welcome user")
name = input("Client name: ")
gender = input("Mr or Miss: ")
age = input("Client age: ")
room = input("Room: ")
sure = input("""All done!!!
Press any key to show the view!""")

welcome = f"""Welcome to room {room} {gender}. {name}!
Have a nice stay"""

pygame.mixer.music.stop()
if pygame.version.vernum >= (2, 0):
    # free some resources. but this exists only for newer
    # versions of pygame
    pygame.mixer.music.unload()

if sure == "a":
    print(welcome)
else:
    print(welcome)