从一个关联数组中减去另一个关联数组中的对应值；删除零值的元素

Question

我有 2 个关联数组，如下所示。

Array
(
    [Turbine] => 0
    [Nuts and Bolts] => 6
    [Runner Blade] => 5
)
Array
(
    [Nuts and Bolts] => 10
    [Runner Blade] => 5
    [Turbine] => 1
)

我想要做的是比较两个数组并返回具有相同键但不同值的数组。与

array_intersect_assoc()

类似，但它返回所有匹配的值，这不是我想要的。使用上面的示例，我想要返回的是两个值之间的差异，例如：

Array
(
    [Nuts and Bolts] => 4
    [Turbine] => 1
)

Answer 1

类似这样的：

$ar1;
$ar2;

foreach ($ar1 as $k => $v) {
    if (intval($ar2[$k]) != intval($v))
        $ar1[$k] = abs($v - $ar2[$k]);
    else
        unset($ar1[$k]);    // remove key with equal value
}

Answer 2

试试这个...

$newArr = array();
foreach($arr1 as $k=>$v){
    $dif = abs($arr1[$k] - $arr2[$k]);
    if($dif) $newArr[$k] = $dif;
}
print '<pre>';
print_r($newArr);

Answer 3

这将实现你想要的：

array_intersect_key($array1, $array2)

Answer 4

$diff = array_diff_assoc($arr1, $arr2);

$result = array();

foreach(array_keys($diff) as $key){
    $result[$key] = abs($arr1[$key] - $arr2[$key]);
}

var_dump($result);

Answer 5

试试这个：

function compareArrays($array1, $array2, $path = "") {
$differences = [];

foreach ($array1 as $key => $value1) {
    $path1 = $path . "[" . $key . "]";

    if (array_key_exists($key, $array2)) {
        $value2 = $array2[$key];

        if (is_array($value1) && is_array($value2)) {
            $subDifferences = compareArrays($value1, $value2, $path1);
            $differences = array_merge($differences, $subDifferences);
        } else {
            if ($value1 !== $value2) {
                $differences[$path1] = $value1;
            }
        }
    } else {
        $differences[$path1] = $value1;
    }
    }

    return $differences;
}

$array1 = array(
    "name" => "John",
    "age" => 30,
    "address" => array(
        "city" => "New York",
        "zipcode" => "10001"
    )
);

$array2 = array(
    "name" => "Alice",
    "age" => 25,
    "address" => array(
        "city" => "Los Angeles",
        "zipcode" => "90001"
    )
);

$differences = compareArrays($array1, $array2);

foreach ($differences as $key => $value) {
    echo "Key: $key, Value: $value\n";
}

此代码的输出将是：

Key: [name], Value: John
Key: [age], Value: 30
Key: [address][city], Value: New York
Key: [address][zipcode], Value: 10001
Key: [name], Value: Alice
Key: [age], Value: 25
Key: [address][city], Value: Los Angeles
Key: [address][zipcode], Value: 90001

Answer 6

如果您不介意改变第二个数组，那么执行一些条件算术并取消设置即可完成工作。

代码：（演示）

$new = [
    'Turbine' => 0,
    'Nuts and Bolts' => 6,
    'Runner Blade' => 5
];
$old = [
    'Nuts and Bolts' => 10,
    'Runner Blade' => 5,
    'Turbine' => 1
];

foreach ($old as $k => &$v) {
    if (empty($new[$k])) {
        continue;          // ignore if key not in $new array or is zero
    }
    $v -= $new[$k];        // subtract new value from old value
    if (!$v) {
        unset($old[$k]);   // if old value has become zero, unset it
    }
}
var_export($old);