我有一个
users
表和一个 roles
表,它们具有 多对多 关系。这两个表连接到一个名为 role_user
的联结表。
以下是我的 Laravel 项目中的模型:
用户
namespace App;
use Illuminate\Database\Eloquent\Model;
class User extends Model
{
public function roles()
{
return $this->belongsToMany('App\Role');
}
}
角色
namespace App;
use Illuminate\Database\Eloquent\Model;
class Role extends Model
{
public function users()
{
return $this->belongsToMany('App\User');
}
}
下面是Laravel项目中的Factory文件:
$factory->define(App\User::class, function (Faker\Generator $faker) {
return [
'name' => $faker->name,
'email' => $faker->unique()->safeEmail,
'password' => $password ?: $password = bcrypt('secret'),
];
});
$factory->define(App\Role::class, function (Faker\Generator $faker) {
return [
'role' => $faker->realText($maxNbChars = 2),
'description' => $faker->realText($maxNbChars = 20),
];
});
以下是 Laravel 项目中的种子文件:
public function run()
{
factory(App\User::class, 50)->create()->each(function ($u) {
$u->roles()->save(factory(App\Role::class)->make());
});
factory(App\Role::class, 20)->create()->each(function ($u) {
$u->users()->save(factory(App\User::class)->make());
});
}
这应该填充
users
表和 roles
表,但是我该如何填充 role_user
表呢? (我没有连接表的模型文件。)
我对此很陌生,因此我们将不胜感激。谢谢。
attach()
或 sync()
方法。
有多种方法可以解决这个问题。这是其中之一:
// Populate roles
factory(App\Role::class, 20)->create();
// Populate users
factory(App\User::class, 50)->create();
// Get all the roles attaching up to 3 random roles to each user
$roles = App\Role::all();
// Populate the pivot table
App\User::all()->each(function ($user) use ($roles) {
$user->roles()->attach(
$roles->random(rand(1, 3))->pluck('id')->toArray()
);
});
另一种方法是使用 saveMany() 函数
public function run()
{
factory(App\User::class,3)->create();
$roles = factory(App\Role::class,3)->create();
App\User::All()->each(function ($user) use ($roles){
$user->roles()->saveMany($roles);
});
}
更简洁的方法可以是:在为 App\User 和 App\Roles 定义工厂后,您可以像这样调用 afterCreating 方法:
$factory->define(App\User::class, function ...);
$factory->define(App\Role::class, function ...);
$factory->afterCreating(App\User::class, function ($row, $faker) {
$row->roles()->attach(rand(1,20));
});
然后在 Seeds 中,您首先创建角色,然后创建用户
public function run()
{
factory(App\Role::class, 20)->create();
factory(App\User::class, 50)->create();
}
现在您有 50 个用户,每个用户都附加一个角色。
仅对于播种机,您可以使用如下内容:
for ($i = 0; $i < 50; $i++) {
$user = factory(App\User::class)->create();
$role = factory(App\Role::class)->create();
DB::table('role_user')->insert([
'user_id' => $user->id,
'role_id' => $role->id
]);
}
但通常你需要定义像有很多通过这样的关系https://laravel.com/docs/5.4/eloquent-relationships#has-many-through
然后您将可以使用:
$user->roles()->save($role);
最好使用这种结构:
App\Role::factory()->count(20)->create();
// Populate users
App\User::factory()->count(50)->create();
// Getting all roles and saving them to variable is not too good idea.
// Instead, get count of rows.
$rolesCount = App\Role::count();
// Populate the pivot table
App\User::all()->each(function ($user) use ($rolesCount) {
$user->roles()->attach(
App\Role::all()->random(rand(1, $rolesCount))->pluck('id')->toArray()
);
});
Laravel 9 及更高版本:
$roles = Role::factory()->count(10)->create();
$user->roles()->attach($roles);