从python gevent输出中删除stacktrace

Question

我是python的新手，并在引发异常时尝试删除/修剪gevent堆栈跟踪输出。我在某处读到了我可以通过使用AsyncResult来实现它，但似乎我无法弄清楚如何使用它。

这是一个我开始并迭代的示例，使其类似于我正在进行故障排除的真实代码，但是当我尝试将my_decor添加到work（）时，我陷入了最后阶段。任何帮助解决这个问题非常感谢。

from gevent.event import AsyncResult
import gevent
from functools import wraps


def my_decor(k, *args, **kwargs):
    @wraps(k)
    def wrapper(*args, **kwargs):
        r = AsyncResult()
        try:
            value = k()
        except Exception as e:
            r.set_exception(e)
        else:
            r.set(value)
        return r.exception or r.value
    result = gevent.spawn(wrapper, k)
    return result


def f():
    def foo():
        if True:
                raise Exception('tttttttt')
    return foo


def p():
    def bar():
        if True:
                raise Exception('ppppppppppppp')
    return bar


@my_decor
def work():
    foo1 = gevent.spawn(f())
    bar1 = gevent.spawn(p())
    gevent.joinall([foo1, bar1])
    return foo1.get() or bar1.get()

Answer 1

找到答案，认为它可能对那些有同样问题的人有所帮助。

from gevent.event import AsyncResult
import gevent
from functools import wraps


def my_decor(k):
    @wraps(k)
    def wrapper(*args, **kwargs):
        r = AsyncResult()
        try:
            value = k(*args, **kwargs)
        except Exception as e:
            r.set_exception(e)
        else:
            r.set(value)
        return r.exception or r.value
    return wrapper


def f(msg):
    @my_decor
    def foo():
        if True:
            raise Exception('tttttttt %s' % msg)
#           print('test')
    return foo


def p(msg):
    @my_decor
    def bar():
        if True:
            raise Exception('ppppppppppppp %s', msg)
    return bar


def work():
    test = "test"
    seti = "set"
    foo1 = gevent.spawn(f(test))  # returns a function that coroutine uses
    bar1 = gevent.spawn(p(seti))
    gevent.joinall([foo1, bar1])
    return foo1.get() or bar1.get()


res = work()
print res