使用公共标识符生成其他观察条件的变量

问题描述 投票:0回答:2

我正在尝试使用调查数据将个人与其父母联系起来。具体来说,我有关于个人是否拥有学位的数据。如果父级有学位,我想创建一个等于1的指标变量。我有一个家庭标识符变量和一个变量,表明个人是父母还是孩子。

如果有人能就我如何做到这一点提供一些建议,那将不胜感激。如果您想提供示例代码,我在R和Stata方面经验丰富。

编辑:

我有这样的事情:

Person Family Characteristic Degree
1        1     Child           No
2        1     Parent          Yes
3        2     Child           No
4        2     Parent          No

我想要这样的东西:

Person Family Characteristic Degree Parent_Degree
1         1       Child        No         1
3         2       Child        No         0
r stata survey
2个回答
1
投票

Stata的解决方案:

clear 
input Person Family str9 Characteristic str3 Degree
1        1     Child           No
2        1     Parent          Yes
3        2     Child           No
4        2     Parent          No
end 

gen byte_Degree = (Degree=="Yes")
bys Family: egen Parent_Degree = total(byte_Degree)
* in case both parents have a degree
replace Parent_Degree = (Parent_Degree > 0)
drop byte_Degree Degree
keep if Characteristic == "Child"

list
     +---------------------------------------+
     | Person   Family   Charac~c   Parent~e |
     |---------------------------------------|
  1. |      1        1      Child          1 |
  2. |      3        2      Child          0 |
     +---------------------------------------+

0
投票

这是使用dplyr库的R解决方案:

library(dplyr)

df %>%

  # within each family, let Parent_Degree be 1 if any parent has a degree
  group_by(Family) %>%
  mutate(Parent_Degree = as.integer(any(Characteristic == "Parent" & Degree == "Yes"))) %>%
  ungroup() %>%

  # keep only child rows
  filter(Characteristic == "Child")

# A tibble: 2 x 5
  Person Family Characteristic Degree Parent_Degree
   <int>  <int> <fctr>         <fctr>         <int>
1      1      1 Child          No                 1
2      3      2 Child          No                 0

数据:

df <- read.table(header = TRUE,
                 text = "Person Family Characteristic Degree
                 1        1     Child           No
                 2        1     Parent          Yes
                 3        2     Child           No
                 4        2     Parent          No")
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