是否可以将嵌套的元组列表转换为numpy数组？

Question

我有一个嵌套的元组列表：

tuple_list = [[(0, 0.022190866145025672),
  (1, 0.03713307553569147),
  (2, 0.03329292095418187),
  (3, 0.013397487788645558),
  (4, 0.012968754425823006),
  (5, 0.02303938132767878),
  (6, 0.5055000245070915),
  (7, 0.02148198409145118)],
 [(0, 0.027141399289287292),
  (1, 0.034094330130799384),
  (2, 0.18793352530921031),
  (3, 0.01545954116652308),
  (4, 0.03658418672184262),
  (5, 0.1929824217980975),
  (6, 0.021051003033754387),
  (7, 0.03489076576637312)]]

您可以，嵌套列表的长度相同。

是否可以将其转换为numpy数组？

我已经尝试过将其转换为这样的numpy数组：

y = numpy.array(tuple_list)

但是我得到这个结果：

array([list([(0, 0.022190866145025672), (1, 0.03713307553569147), (2, 0.03329292095418187), (3, 0.013397487788645558), (4, 0.012968754425823006), (5, 0.02303938132767878), (6, 0.5055000245070915), (7, 0.02148198409145118), (8, 0.028544808844256947), (9, 0.023656766961056515), (10, 0.058975765442311284), (11, 0.052628865356187236), (12, 0.019632103194206267), (13, 0.017715501743987942), (14, 0.013181486857172771), (15, 0.03693920037515881), (16, 0.059811388273952625), (17, 0.019909618176120435)]),
       list([(0, 0.027141399289287292), (1, 0.034094330130799384), (2, 0.18793352530921031), (3, 0.01545954116652308), (4, 0.03658418672184262), (5, 0.1929824217980975), (6, 0.021051003033754387), (7, 0.03489076576637312), (8, 0.027263833771125616), (9, 0.022274146808526914), (10, 0.1321132498202665), (11, 0.034287197030052854), (12, 0.021483869200653788), (13, 0.033468696091416075), (14, 0.014070713898823948), (15, 0.029487668742227795), (16, 0.025213173521698867), (17, 0.11020027789932013)])

我想要的结果将是这样：

array([[(0, 0.022190866145025672),
  (1, 0.03713307553569147),
  (2, 0.03329292095418187),
  (3, 0.013397487788645558),
  (4, 0.012968754425823006),
  (5, 0.02303938132767878),
  (6, 0.5055000245070915),
  (7, 0.02148198409145118)],
  [(0, 0.027141399289287292),
  (1, 0.034094330130799384),
  (2, 0.18793352530921031),
  (3, 0.01545954116652308),
  (4, 0.03658418672184262),
  (5, 0.1929824217980975),
  (6, 0.021051003033754387),
  (7, 0.03489076576637312)]])

作为进一步的信息，我需要数组中的嵌套列表来计算两个分布之间的Jesen-Shannon散度。

Answer 1

您可以使用numpy检出此内容：

lst = [[(0, 0.022190866145025672),
  (1, 0.03713307553569147),
  (2, 0.03329292095418187),
  (3, 0.013397487788645558),
  (4, 0.012968754425823006),
  (5, 0.02303938132767878),
  (6, 0.5055000245070915),
  (7, 0.02148198409145118)],
 [(0, 0.027141399289287292),
  (1, 0.034094330130799384),
  (2, 0.18793352530921031),
  (3, 0.01545954116652308),
  (4, 0.03658418672184262),
  (5, 0.1929824217980975),
  (6, 0.021051003033754387),
  (7, 0.03489076576637312)]]


import numpy as np
print(np.array(lst))