客户端代码是100%正常的,因为我用它连接了一个别人做的服务器。现在我试着做我自己的服务器。有谁知道为什么不能用?我在服务器应用程序中没有得到任何错误,但它从来没有进入第二个线程。
客户端代码。
public void connectToServer(){ (used in some activity)
new AsyncTask<Void, Void, Void>() {
@Override
protected Void doInBackground(Void... voids) {
try {
socket = new Socket("192.168.0.1", 9999);
send = new PrintWriter(new BufferedWriter(new OutputStreamWriter(socket.getOutputStream())), true);
get = new BufferedReader(new InputStreamReader(socket.getInputStream()));
}catch (Exception ex){
Log.e("connection", ex.toString());
}
return null;
}
}.execute();
}
服务器代码:
class MainActivity : AppCompatActivity() {
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
findViewById<Button>(R.id.buttonStartServer).setOnClickListener {
Log.e("Button", "Apasat")
val server = ServerSocket(9999, 10, InetAddress.getByName("0.0.0.0"))
thread {
run {
Log.e("first run check server", server.inetAddress.hostAddress)
Log.e("first run", "waiting for clients")
while (true) {
val client = server.accept()
Log.e("first run", "got a client")
thread {
run {
Log.e("second run", "waiting for messages")
val reader = Scanner(client.getInputStream())
val writer: OutputStream = client.getOutputStream()
while(true) {
try {
val text = reader.nextLine()
writer.write((text + '\n').toByteArray(Charset.defaultCharset()))
}catch (ex: Exception){
Log.e("client" + client.inetAddress.hostAddress, ex.toString())
}
}
}
}
}
}
}
}
}
}
代码工作正常,但因为我的服务器是在Android上运行,我需要设置服务器设备模拟器,像这里。https:/developer.android.comstudiorunemulator -networking#connecting。
而有人问到这里该如何设置。两个Android模拟器之间的通信 他得到步骤解释的地方。