我正在尝试将implements Parcelable
从一个活动传递给一个片段。我知道如何从活动转到活动。我只想试试这个。但当我收到物体时,它总是收到null
。我该如何解决这个问题?
currentObject
是实现Parcelable的类的对象实例
ContentMainFragment
是片段类
在活动中
Fragment fragment = new ContentMainFragment();
Bundle bundle = new Bundle();
bundle.putParcelable("SampleObject", currentObject);
fragment.setArguments(bundle);
在片段中
Bundle bundle = this.getArguments();
if (bundle != null) {
currentObject = bundle.getParcelable("SampleObject");
link = currentObject.getLink();
}
谢谢。
试试这个
首先,改变一些小事。
main activity.Java
// 1. Parse the object to the fragment as a bundle;
ContentMainFragment contentMainFragment = new ContentMainFragment();
Bundle bundle = new Bundle();
bundle.putParcelable("SampleObject", currentObject);
contentMainFragment.setArguments(bundle);
// 2. Commit the fragment.
getSupportFragmentManager().beginTransaction()
.add(R.id.fragment_container, contentMainFragment).commit();
content main fragment.Java
// 1. Get the object in onCreate();
if (getArguments() != null) {
link = getArguments().getParcelable("SampleObject").getLink();
}
其次,您的方法似乎没有问题,然后仔细检查您是否正在解析Activity中的有效对象(currentObject)。
我给你看了一些代码来帮助你:
模型
public class Model implements Parcelable {
private String name;
public Model(){
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
protected Model(Parcel in) {
name = in.readString();
}
public static final Creator<Model> CREATOR = new Creator<Model>() {
@Override
public Model createFromParcel(Parcel in) {
return new Model(in);
}
@Override
public Model[] newArray(int size) {
return new Model[size];
}
};
@Override
public int describeContents() {
return 0;
}
@Override
public void writeToParcel(Parcel parcel, int i) {
parcel.writeString(name);
}
}
主要信息
Model currentObject = new Model();
currentObject.setName("Testing arguments");
TestFragment fragment = new TestFragment();
Bundle bundle = new Bundle();
bundle.putParcelable("SampleObject", currentObject);
fragment.setArguments(bundle);
TestFragment
public class TestFragment extends Fragment {
Model model;
public TestFragment() {
// Required empty public constructor
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
Bundle bundle = this.getArguments();
if (bundle != null) {
model = bundle.getParcelable("SampleObject");
}
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
// Inflate the layout for this fragment
View v = inflater.inflate(R.layout.fragment_test, container, false);
TextView tvArgument = v.findViewById(R.id.tvTestArgument);
tvArgument.setText(model.getName());
return v;
}
}
此代码正常工作。
但通常在我的情况下,我必须在活动或碎片之间传递数据。我没有实现Parcelable。我使用Serializable因为实现起来更快。
Serializable示例:
模型
public class Model implements Serializable {
private String name;
public Model(){
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
protected Model(Parcel in) {
name = in.readString();
}
}
主要信息
Model currentObject = new Model();
currentObject.setName("Testing arguments");
TestFragment fragment = new TestFragment();
Bundle bundle = new Bundle();
bundle.putSerializable("SampleObject");
TestFragment
public class TestFragment extends Fragment {
Model model;
public TestFragment() {
// Required empty public constructor
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
Bundle bundle = this.getArguments();
if (bundle != null) {
model = (Model) bundle.getSerializable("SampleObject");
}
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
// Inflate the layout for this fragment
View v = inflater.inflate(R.layout.fragment_test, container, false);
TextView tvArgument = v.findViewById(R.id.tvTestArgument);
tvArgument.setText(model.getName());
return v;
}
}
我希望它对你有所帮助。
您需要将分配更改为要使用的类而不是父类来接收bundle
数据,
在这里编辑:
改成
ContentMainFragment fragment = new ContentMainFragment(); //Updated
代替
Fragment fragment = new ContentMainFragment(); //Old