Python 3-当满足要求时，while循环不会脱离循环

Question

我简单的石头，纸，剪刀代码：

def game(item1,item2,score1,score2):
   while score1 <= 3 or score2 <= 3 :
          item1 = input("Rock,Paper or Scissors?(1) ")
          item2 = input("Rock,Paper or Scissors?(2) ")
          if item1 == item2:
                 print("It´s a tie! ")
          elif item1 == "Rock":
                 if item2 == "Scissors":
                        score1 +=1
                        print("Player1 wins and has a score of",score1)
                 else:
                        score2 +=1
                        print("Player2 wins and has a score of",score2)
          elif item1 == "Scissors":
                 if item2 == "Paper":
                        score1 +=1
                        print("Player1 wins and has a score of",score1)
                 else:
                        score2 +=1
                        print("Player2 wins and has a score of",score2)
          elif item1 == "Paper":
                 if item2 == "Rock":
                        score1 +=1
                        print("Player1 wins and has a score of",score1)
                 else:
                        score2 +=1
                        print("Player2 wins and has a score of",score2)
          else:
                 print("Invalid input, try again")

当我尝试并达到3分时，它仍然不断要求我输入，只有当我在score1和score2中均达到3分时，它才中断循环。为什么？我使用“或”运算符是否错误？

Answer 1

虽然score1或score2小于等于3，但直到两个玩家的得分都高于3时，它才会保持为真。

正确的条件是，只要两个玩家的得分都小于3，就继续前进。当任一得分变为3时，游戏结束。>

def game():
   score1, score2 = 0, 0
   while score1 < 3 and score2 < 3:  # while neither have won
          item1 = input("Rock,Paper or Scissors?(1) ")
          item2 = input("Rock,Paper or Scissors?(2) ")
          if item1 == item2:
                 print("It´s a tie! ")
          elif item1 == "Rock":
                 if item2 == "Scissors":
                        score1 +=1
                        print("Player1 wins and has a score of",score1)
                 else:
                        score2 +=1
                        print("Player2 wins and has a score of",score2)
          elif item1 == "Scissors":
                 if item2 == "Paper":
                        score1 +=1
                        print("Player1 wins and has a score of",score1)
                 else:
                        score2 +=1
                        print("Player2 wins and has a score of",score2)
          elif item1 == "Paper":
                 if item2 == "Rock":
                        score1 +=1
                        print("Player1 wins and has a score of",score1)
                 else:
                        score2 +=1
                        print("Player2 wins and has a score of",score2)
          else:
                 print("Invalid input, try again")

game()
输出：

Rock,Paper or Scissors?(1) Rock
Rock,Paper or Scissors?(2) Paper
Player2 wins and has a score of 1
Rock,Paper or Scissors?(1) Rock
Rock,Paper or Scissors?(2) Paper
Player2 wins and has a score of 2
Rock,Paper or Scissors?(1) Rock
Rock,Paper or Scissors?(2) Paper
Player2 wins and has a score of 3

Process finished with exit code 0

Answer 2

让我为您分解，