Pic16f88和Sim900模块无响应

Question

我正在编写代码来制作一个通过短信打开微控制器端口的模块。我正在使用Pic16F88和Sim900模块，正在mplab X和XC8中编程。它在Proteus中工作，但在电路中没有，我已经解决了一些电容器的功耗问题，因此我认为问题出在代码中。也许模块无法将'\ r'字符识别为回车符？

    /*
 * File:   ContGsmMain.c
 * Author: camil
 *
 * Created on 28 de enero de 2020, 22:08
 */

// CONFIG1
#pragma config FOSC = INTOSCIO  // Oscillator Selection bits (INTRC oscillator; port I/O function on both RA6/OSC2/CLKO pin and RA7/OSC1/CLKI pin)
#pragma config WDTE = OFF       // Watchdog Timer Enable bit (WDT disabled)
#pragma config PWRTE = OFF      // Power-up Timer Enable bit (PWRT disabled)
#pragma config MCLRE = ON       // RA5/MCLR/VPP Pin Function Select bit (RA5/MCLR/VPP pin function is MCLR)
#pragma config BOREN = ON       // Brown-out Reset Enable bit (BOR enabled)
#pragma config LVP = OFF        // Low-Voltage Programming Enable bit (RB3 is digital I/O, HV on MCLR must be used for programming)
#pragma config CPD = OFF        // Data EE Memory Code Protection bit (Code protection off)
#pragma config WRT = OFF        // Flash Program Memory Write Enable bits (Write protection off)
#pragma config CCPMX = RB0      // CCP1 Pin Selection bit (CCP1 function on RB0)
#pragma config CP = OFF         // Flash Program Memory Code Protection bit (Code protection off)

// CONFIG2
#pragma config FCMEN = OFF       // Fail-Safe Clock Monitor Enable bit (Fail-Safe Clock Monitor enabled)
#pragma config IESO = OFF       // Internal External Switchover bit (Internal External Switchover mode disabled)

#define _XTAL_FREQ 8000000
#include <xc.h>
#include "pic16f88.h"
#include "uart.h"
#include <string.h>
#include <stdio.h>
#include <stdlib.h>

//Funcion retorna la posición donde comienza la cadena seleccionada
int existe(char linea[], char busq[]);

void main(void) {
    TRISA=0;                // Program Init
    TRISB=0x04;
    PORTA=0;
    PORTB=0;
    OSCCON = 0b01111100;
    UART_Init(9600);
    __delay_ms(200);

    int porta[8]={0,0,0,0,0,0,0,0};     //Variable declaration
    char buffer[80]="";
    char *buff;
    char textbuf[10]="";
    int i=0,e=0;
    buff=buffer;

    RA3=1;                          //Module Init
     __delay_ms(3000);
     RA3=0;
    UART_Write_Text("AT+CMGF=1\r");
    __delay_ms(100);
    UART_Write_Text("AT+IPR=9600\r");
    __delay_ms(100);
    UART_Write_Text("AT+CNMI=2,2,0,0,0\r");   
    __delay_ms(100);     

    while(1){
            if(RCIF==1){                // Try if message is received
             for(i=0;i<80;i++){
                while(!RCIF);
                buff[i]=UART_Read();
                if(buff[i]=='\r') 
                     break; 
                }

     /*          itoa(textbuf,existe(buff, "L"),10 );      //Debugging segment
                  UART_Write_Text(textbuf);  */

                if(existe(buffer, "L")==1) {
                    porta[2]=!porta[2];
                    RA2=porta[2];

                /*  itoa(textbuf,porta[3],10 );     //Debugging segment
                UART_Write_Text("Existe ");
                UART_Write_Text(textbuf);
                UART_Write_Text("\r");*/
                }

                for(i=0;i<80;i++) buff[i]=0;             
            }
        }
}

int existe(char linea[], char busq[]){
    int e=0,a=0;
    char *carpal, *carbus;
    carpal=linea;
    carbus=busq;
    for(e=0;e<strlen(linea);e++){
        if(carpal[e]==carbus[a]){
            a++;
            if(a==strlen(busq)){
                return 1;
                }
            continue;
        }
        else a=0;
    }
    return 0;
   }

Answer 1

最后我确实解决了2个问题：

-使用命令“ UART1_Write_Text（” AT + ICF = 3,0 \ r“）;”这使得GSM模块使用软件流控制而不是硬件控制。使用此解决方案时，对“ L”之类的小输入有反应，但是当我将输入更改为“ Luz”之类时，它就不起作用了。

-然后我确实在输入中使用了控制字符来破坏if（buff [i] =='\ r'）的循环，在这种情况下为'_'。

我认为问题在于模块在发送“ Luz”输入之前先发送了“ \ r”字符。然后，它退出循环并开始处理，直到UART停止接收为止，然后当微型计算机执行其余代码时，recevinig 3个字符给出错误标志。使用“ Luz_”输入，并在收到“ _”后立即停止阅读。