如何将列表列表组合成python中的字符串

Question

我有一个包含多个列表的列表，我想将这些列表合并为单个字符串，以便可以在其上使用counter（）方法。

样本列表

 List1= [
     ['this is the first document',
     'this document is the second document'],
     ['and this is the third one',
     'is this the first document']]

需要输出“这是第一个文件，这个文件是第二个文件，这是第三个文件，这是第一个文件”

谢谢。

Answer 1

您可以使用内置的join()功能：

list = [ 'this is the first document', 'this document is the second document', 'and this is the third one', 'is this the first document']
print(', '.join(list))

输出：

this is the first document, this document is the second document, and this is the third one, is this the first document

Answer 2

使用.join（）方法：

list1= ['this is the first document', 'this document is the second document', 'and this is the third one', 'is this the first document']

list1_joined = ",".join(list1)
print(list1_joined)

#Output:
'this is the first document,this document is the second document,and this is the third one,is this the first document'

Answer 3

创建一个计数器对象，并使用object_name.element（）遍历并打印。

  c = Counter(List1) 
  for i in c.elements(): 
       print ( i, end = " ")

有关详细信息，[https://www.geeksforgeeks.org/python-counter-objects-elements/][1]

Answer 4

遍历整个列表并追加到字符串。

类似的东西

l = [['...','..'],['..']...]
result = ''
for sublist in l:
  for item in sublist:
    result += item

Answer 5

outer_list = [["innerlist1element1", "innerlist1element2"],["innerlist2element1","innerlist2element2"]]
res_string = ""
for innerlist in outer_list:
    res_string+= ' '.join(innerlist)+" "
print(res_string)

for循环遍历外部列表中的列表，join（）将其所有元素连接在一起，并在两者之间留有空格。但是，要连接结果字符串，将使用良好的旧串联'+'。

用列表理解替换循环：

outer_list = [["innerlist1element1", "innerlist1element2"],["innerlist2element1","innerlist2element2"]]
a = [' '.join(i) for i in outer_list]
print(' '.join(a))

列表理解更快，更易读。在python docs中查看更多。