android WeakReference的活动

问题描述 投票:0回答:1

我有一个异步任务,我发出警告,它应该是静态的,否则可能会发生泄漏。

所以我使用了像这样的WeakReference:

 private static class GetContacts extends AsyncTask<String, Void, Boolean> {
    ProgressDialog dialog;
    private WeakReference<Novinky> activityReference;

    GetContacts(Novinky context) {
        activityReference = new WeakReference<>(context);
    }

    @Override
    protected void onPreExecute() {
        // get a reference to the activity if it is still there
        Novinky activity = activityReference.get();
        if (activity == null || activity.isFinishing()) return;
        super.onPreExecute();
        dialog = new ProgressDialog(activity);
        dialog.setMessage("Načítavam");
        dialog.setTitle("Pripájam sa k serveru");
        dialog.show();
        dialog.setCancelable(false);
    }

    @Override
    protected Boolean doInBackground(String... args) {
        HttpHandler sh = new HttpHandler();
        String url = "https://www...";
        String jsonStr = sh.makeServiceCall(url);

        if (jsonStr != null) {
            try {JSONObject jsonObj = new JSONObject(jsonStr);
                JSONArray actors = jsonObj.getJSONArray("result");

                for (int i = 0; i < actors.length(); i++) {
                    JSONObject c = actors.getJSONObject(i);

                    Actors actor = new Actors();

                    actor.setLetter(c.getString("letter"));
                    actor.setNazov(c.getString("name"));
                    actor.setPerex(c.getString("perex"));

                    actorsList.add(actor);
                }

            }  catch (final JSONException e) {
                        Novinky.this.runOnUiThread(new Runnable() {
                    @Override
                    public void run() {
                        Toast.makeText(Novinky.this.getApplicationContext(),
                                "Chyba dát: " + e.getMessage(),
                                Toast.LENGTH_LONG).show();
                    }
                }); }

            return true;

        } else {
                Novinky.this.runOnUiThread(new Runnable() {
                @Override
                public void run() {
                    Toast.makeText(Novinky.this.getApplicationContext(),
                            "Chyba internetového pripojenia.",
                            Toast.LENGTH_LONG).show();
                }
            });
            return false;
        }
    }

    protected void onPostExecute(Boolean result) {
        // get a reference to the activity if it is still there
        Novinky activity = activityReference.get();
        if (activity == null || activity.isFinishing()) return;
        super.onPostExecute(result);
        dialog.dismiss();
        adapter.notifyDataSetChanged();
    }
}

现在警告已经消失了,但是我还在与其他一些由于我的变化而出现的错误作斗争。

1 / actorsList.add(actor); - 在我的for循环中现在说非静态字段'actorsList'不能从静态上下文中引用

2 /在catch和else语句中放置runOnUiThread我遇到Novinky.this.runOnUiThread问题 - 无法从静态上下文引用

如果我只是用WeakReference(activityReference)替换Novinky.this,那么它会说类名是预期的,所以不确定如何在这些线程中正确替换Novinky.this。

我也尝试使用Novinky activity = activityReference.get();然后使用activity.runOnUiThread - 这删除了错误,但Novinky activity = activityReference.get();的定义然后警告此字段泄漏上下文对象

3 /最后一个问题出在我的onPostExecute - adapter.notifyDataSetChanged();上。错误说明:无法从静态上下文引用非静态字段“适配器”

更新:我以某种方式解决了它,现在我没有错误,应用程序正在运行,但仍然不确定我是否正确解决了它:

对于1 / I在主类中定义了static ArrayList<Actors> actorsList;

2 /在捕获,否则我定义了final Novinky activity = activityReference.get();

然后:

activity.runOnUiThread

3 / in onPostExecute我使用了activity.adapter.notifyDataSetChanged();

android android-asynctask weak-references
1个回答
1
投票

您应该能够以访问适配器的方式访问列表实例:

activityReference.get().actorsList
© www.soinside.com 2019 - 2024. All rights reserved.