从Node.js调用Java Lambda函数

Question

我有一个用Java编写的Lambda函数，我想从NodeJS调用它。这可能吗？我收到以下错误：

An error occurred during JSON parsing: java.lang.RuntimeException
java.lang.RuntimeException: An error occurred during JSON parsing
Caused by: java.io.UncheckedIOException: com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of java.lang.String out of START_OBJECT token
at [Source: lambdainternal.util.NativeMemoryAsInputStream@5dc0ff7d; line: 1, column: 1]
Caused by: com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of java.lang.String out of START_OBJECT token
at [Source: lambdainternal.util.NativeMemoryAsInputStream@5dc0ff7d; line: 1, column: 1]
at com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:148)
at com.fasterxml.jackson.databind.DeserializationContext.mappingException(DeserializationContext.java:857)
at com.fasterxml.jackson.databind.deser.std.StringDeserializer.deserialize(StringDeserializer.java:62)
at com.fasterxml.jackson.databind.deser.std.StringDeserializer.deserialize(StringDeserializer.java:11)
at com.fasterxml.jackson.databind.ObjectReader._bindAndClose(ObjectReader.java:1511)
at com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:1102)

这是我的Lambda的代码：

public String handleRequest(String input, Context context) {
  context.getLogger().log("input: " + input + "\n");
  JSONObject obj = new JSONObject(input);
  String dest_key = obj.getString("key");
  context.getLogger().log("key: " + dest_key + "\n");

  ...
}

这是我的JavaScript调用上面的Lambda：

const AWS = require('aws-sdk');

const payload = "{\"key\": \"slide.pptx\"}"

AWS.config.loadFromPath('./config.json');
const lambda = new AWS.Lambda({ region: "ap-south-1" });
const params = {
  FunctionName : 'slide-builder',
  InvocationType : 'RequestResponse',
  Payload: payload // I get the same error even without a payload
};

lambda.invoke(params, function(err, data) {
  if (err) console.log(err, err.stack);
  else console.log(JSON.stringify(data));
});

Answer 1

您有两个选项可以比您拥有的更好。尝试获取String对我来说从未起作用，因为Java Lambda会在您获取之前尝试解释JSON有效内容。

一种选择是消除Lambda尝试对输入对象进行任何解释。就像是：

import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;

public void handleRequest(InputStream inputStream,
                          OutputStream outputStream,
                          Context context) throws IOException {

    ObjectMapper objectMapper = new ObjectMapper();
    JsonNode jsonNode = objectMapper.readTree(inputStream);
    String key= jsonNode.get("key").asText();
    // key will now be "slide.pptx"

    // create object to return...
    MyObject myObject = new MyObject();

    // create JSON string
    String jsonReturn = objectMapper.writeValueAsString(myObject);

    // "return" the string
    outputStream.write(jsonReturn .getBytes(Charset.forName("UTF-8")));
}

当您尝试将传入数据转换为所需对象时，您所做的就是避免Java Lambda“有用”。当你有一个完整的对象但是没有做你想做的事情时，这种方法很有效。

另一种选择是创建一个镜像Node对象的对象：

public class KeyObject {
    private String key;

    public String getKey() {
        return key;
    }
}

然后让你的处理函数为：

public String handleRequest(KeyObject key, Context context) {

    String fileName = key.getKey();

    // return as you're doing now.
}

我相信其中任何一个都会做你想要的。

Answer 2

(From this answer)

public class LambdaFunctionHandler implements RequestHandler<Map<String,Object>, String> {
    public String handleRequest(Map<String,Object> input, Context context) {
        context.getLogger().log(input.get("key"));
        ...
    }
}

我对stdunbar的解决方案没什么好运，但这对我有用。