如何解析修复“无效的用户名/密码”

问题描述 投票:2回答:1

我正在开发使用解析服务器具有signupLogin一个应用程序,其中我能够立即登记,但是当我尝试登录它给了我异常

“无效的用户名/密码”

这是signUpLogIn代码,当signUpMode是活跃用户。或者按下按钮时signUpmode是去活,即假的按钮作为登录,用户可以登录,但这里的时候,我尝试登录signedup其说“无效用户名密码”

  public void signUp(View view)
        {
            editTextUser =(EditText) findViewById(R.id.userNameEdit);
            editTextPass =(EditText) findViewById(R.id.passWordEdit);

                if(editTextUser.getText().toString().matches("") || editTextPass.getText().toString().matches(""))
                {
                    Toast.makeText(this,"Username and Password required",Toast.LENGTH_SHORT).show();
                }
                else
                {
                    if(SignupModeActive)
                    {
                        ParseUser user = new ParseUser();
                        user.setUsername(editTextUser.getText().toString());
                        user.setPassword(editTextUser.getText().toString());
                        user.signUpInBackground(new SignUpCallback() {
                            @Override
                            public void done(ParseException e) {

                                    if(e == null)
                                    {
                                        Log.i("saveInBackGround","SignUp Success");
                                        Intent intent = new Intent(MainActivity.this,UserslistActivity.class);
                                        startActivity(intent);
                                    }
                                    else{
                                        Toast.makeText(MainActivity.this,e.getMessage(),Toast.LENGTH_SHORT).show();
                                    }


                            }
                        });


                    }
                    else
                    {
                            ParseUser.logInInBackground(editTextUser.getText().toString(),editTextPass.getText().toString(), new LogInCallback() {
                                @Override
                                public void done(ParseUser user, ParseException e) {
                                    if(user != null){
                                        Log.i("LogInBackGround","Login Succesfull");
                                        Intent logInintent = new Intent(MainActivity.this,UserslistActivity.class);
                                        startActivity(logInintent);
                                    }
                                    else
                                    {
                                        Toast.makeText(MainActivity.this,e.getMessage(),Toast.LENGTH_LONG).show();
                                    }
                                }
                            });
                        }


                    }



                }
android parse-server
1个回答
0
投票

//检查异常

public void signUp(View view)
        {
            mEditTextUser =(EditText) findViewById(R.id.userNameEdit);
            mEditTextPass =(EditText) findViewById(R.id.passWordEdit);

                if(mEditTextUser .getText().toString().trim().length()==0 || editTextPass.getText().toString().trim().length()==0.matches(""))
                {
                    Toast.makeText(this,"Username and Password required",Toast.LENGTH_SHORT).show();
                }
                else
                {
                 //Check SignupMode is true
   if(SignupModeActive)
                    {
                        ParseUser user = new ParseUser();
                        user.setUsername(editTextUser.getText().toString());
                        user.setPassword(editTextUser.getText().toString());
                        user.signUpInBackground(new SignUpCallback() {
                            @Override
                            public void done(ParseException e) {

                                    if(e == null)
                                    {
                                        Log.e("Exception",e.printStackTrace());
                                        Intent intent = new Intent(MainActivity.this,UserslistActivity.class);
                                        startActivity(intent);
                                    }
                                    else{
                                        Toast.makeText(MainActivity.this,e.getMessage(),Toast.LENGTH_SHORT).show();
                                    }


                            }
                        });


                    }
                    else
                    {
                            ParseUser.logInInBackground(editTextUser.getText().toString(),editTextPass.getText().toString(), new LogInCallback() {
                                @Override
                                public void done(ParseUser user, ParseException e) {
                                    if(user != null){
                                        Log.i("LogInBackGround","Login Succesfull");
                                        Intent logInintent = new Intent(MainActivity.this,UserslistActivity.class);
                                        startActivity(logInintent);
                                    }
                                    else
                                    {
                                        Toast.makeText(MainActivity.this,e.getMessage(),Toast.LENGTH_LONG).show();
                                    }
                                }
                            });
                        }


                    }



                }
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