将嵌套循环查询与父数组结果 - pg-promise相结合

问题描述 投票:4回答:3

我是node(express)和pg-promise的新手,并且无法弄清楚如何将每个嵌套查询(循环)的结果添加到主json数组结果查询中。

我有两张桌子:帖子和评论。

CREATE TABLE post(
id serial,
content text not null,
linkExterno text,
usuario VARCHAR(50) NOT NULL REFERENCES usuarios(alias) ON UPDATE cascade ON DELETE cascade,
multimedia text,
ubicacation VARCHAR(100),
likes integer default 0,
time VARCHAR default now(),
reported boolean default false,
PRIMARY KEY (id)  );

CREATE TABLE comment(
id serial,
idPost integer NOT NULL REFERENCES post(id) ON UPDATE cascade ON DELETE cascade,
acount VARCHAR(50) NOT NULL REFERENCES users(alias) ON UPDATE cascade ON DELETE cascade,
content text NOT NULL,
date date default now(),
PRIMARY KEY (id));

所以我想将每条评论的结果添加到每个帖子并返回帖子。我有这个,但不起作用:

con.task(t => {
    return t.any('select *, avatar from post, users where user= $1 and user = alias ORDER BY time DESC LIMIT 10 OFFSET $2', [username, pos])
    .then(posts => {
        if(posts.length > 0){
            for (var post of posts){
                post.coments = t.any('select * from comment where idPost = $1 ', post.id);
            }
        }
    });
}).then(posts => {
    res.send(posts);
}).catch(error => {
    console.log(error);
});

有什么建议? PD:我认为我的问题与此类似:get JOIN table as array of results with PostgreSQL/NodeJS

解答:

选项1(最佳选择):

通过JSON对psql进行单个查询(JSON查询)

请参阅@ vitaly-t的回答

要么

使用ajax异步获取嵌套数据。

选项2:

function buildTree(t) {
        return t.map("select *, avatar from publicacion, usuarios where usuario = $1 and usuario = alias ORDER BY hora DESC LIMIT 10 OFFSET $2", [username, cantidad], posts => {
                return t.any('select * from comentario where idPublicacion = $1', posts.id)
                    .then(coments => {
                        posts.coments = coments;
                        console.log(posts.coments);
                        return posts;
                    });
        }).then(t.batch); // settles the array of generated promises
    }

    router.get('/publicaciones', function (req, res) {
        cantidad = req.query.cantidad || 0; //num de publicaciones que hay
        username = req.session.user.alias;

        con.task(buildTree)
        .then(data => {
            res.send(data);
        })
        .catch(error => {
            console.log(error);
        });
    });

选项3(异步):

try{
    var posts = await con.any('select *, avatar from post, users where user = $1 and user = alias ORDER BY time DESC LIMIT 10 OFFSET $2', [username, q])
    for (var post of posts){
        post.coments = await con.any('select * from comment where idPublictcion = $1', post.id);
    }
}catch(e){
    console.log(e);
}
node.js postgresql express promise pg-promise
3个回答
3
投票

我是pg-promise的作者;)


con.task(t => {
    const a = post => t.any('SELECT * FROM comment WHERE idPost = $1', post.id)
        .then(comments => {
            post.comments = comments;
            return post;
        });
    return t.map('SELECT *, avatar FROM post, users WHERE user = $1 AND user = alias ORDER BY time DESC LIMIT 10 OFFSET $2', [username, pos], a)
        .then(t.batch);
})
    .then(posts => {
        res.send(posts);
    })
    .catch(error => {
        console.log(error);
    });

另见这个问题:get JOIN table as array of results with PostgreSQL/NodeJS

UPDATE

如果您不想一直使用JSON查询方法,那么以下内容将比原始解决方案更好地扩展,因为我们连接所有子查询,然后将它们作为一个查询执行:

con.task(async t => {
    const posts = await t.any('SELECT *, avatar FROM post, users WHERE user = $1 AND user = alias ORDER BY time DESC LIMIT 10 OFFSET $2', [username, pos]);
    const a = post => ({query: 'SELECT * FROM comment WHERE idPost = ${id}', values: post});
    const queries = pgp.helpers.concat(posts.map(a));
    await t.multi(queries)
        .then(comments => {
            posts.forEach((p, index) => {
                p.comments = comments[index];
            });
        });
    return posts;
})
    .then(posts => {
        res.send(posts);
    })
    .catch(error => {
        console.log(error);
    });

见API:


1
投票

如果您想要结构化(嵌套)数据,而不必

A)使用json函数重新编写sql,或将其拆分为多个任务查询,或者

B)重构你的代码以使用重ORM的API

你可以看看sql-toolkit。它是为pg-promise构建的节点库,它允许您编写常规本机SQL并接收正确结构化(嵌套)的纯业务对象。它绝对是pg-promise之上的增强工具包,并不寻求抽象出pg-promise(你仍然设置了pg-promise并且可以直接使用它)。

例如:

class Article extends BaseDAO {
  getBySlug(slug) {
    const query = `
      SELECT
        ${Article.getSQLSelectClause()},
        ${Person.getSQLSelectClause()},
        ${ArticleTag.getSQLSelectClause()},
        ${Tag.getSQLSelectClause()}
      FROM article
      JOIN person
        ON article.author_id = person.id
      LEFT JOIN article_tags
        ON article.id = article_tags.article_id
      LEFT JOIN tag
        ON article_tags.tag_id = tag.id
      WHERE article.slug = $(slug);
  `;
  return this.one(query, { slug });
  // OUTPUT: Article {person: Person, tags: Tags[Tag, Tag, Tag]}
}

select子句使用业务对象“getSQLSelectClause”方法在输入列时保存乏味,并确保没有名称冲突(没有什么神奇的事情发生,而只能写出来)。

this.one是对sql-toolkits基础DAO类的调用。它负责将平面结果记录结构化为一个漂亮的嵌套结构。

(另请注意,它是“one”,它与我们的SQL的心智模型相匹配.DAO方法为one,oneOrNone,many和any确保它们的计数与生成的顶级业务对象的数量 - 而不是sql的行数表达式返回!)

查看qazxsw poi,了解如何在qazxsw poi上设置它的详细信息。 (免责声明,我是repository的作者。)


0
投票

您可以使用pg-promise但它将同步工作。

sql-toolkit

其实我建议你使用书架,knex,typeorm等orm工具

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