等forkjoin来渲染html

Question

我有一个forkjoin有2个电话。在html，我需要等到forkjoin的回应到来。用async管道有什么办法吗？我在另一篇文章中读到async仅适用于observables和promises。我尝试用*ngIf做，但它不起作用。提前致谢

TS

var1: string;
var2: string;

 forkJoin(
   this.call1(),
   this.call2()
 ).subscribe(([res1, res2]) => {
   this.var1 = res1;
   this.var2 = res2;
   }, err => console.log(err));

HTML

<div class="col">
   <label class="labelEsp">Var 1:</label>
   <span class="spanEsp uppercase" >{{ var1 }}</span>
</div>
<div class="col">
    <label class="labelEsp"> Var 2:</label>
    <span class="spanEsp" >{{ var2 }}</span>
</div>

Answer 1

您可以继续在typescript中使用订阅，并使用标记隐藏并在视图中显示HTML。

这样的事情会做：

dataReady = false;
forkJoin(
   this.call1(),
   this.call2()
 ).subscribe(([res1, res2]) => {
   this.var1 = res1;
   this.var2 = res2;
   },
 (err) => console.log(err),
 () => {
    this.dataReady = true
    // complete block
  }
);

<ng-container *ngIf="dataReady else loading">
  <div class="col">
    <label class="labelEsp">Var 1:</label>
    <span class="spanEsp uppercase" >{{ var1 }}</span>
  </div>
  <div class="col">
      <label class="labelEsp"> Var 2:</label>
      <span class="spanEsp" >{{ var2] }}</span>
  </div>
</ng-container>

<ng-template #loading>
  loading...
</ng-template>

如果你想使用async管道本身，那么你可以有类似的东西：

data = forkJoin(
   this.call1(),
   this.call2()
 )


<ng-container *ngIf="data | async as resolvedData else loading">
  <div class="col">
    <label class="labelEsp">Var 1:</label>
    <span class="spanEsp uppercase" >{{ resolvedData[0] }}</span>
  </div>
  <div class="col">
      <label class="labelEsp"> Var 2:</label>
      <span class="spanEsp" >{{ resolvedData[1] }}</span>
  </div>
</ng-container>

<ng-template #loading>
  loading...
</ng-template>

在这里查看示例：https://stackblitz.com/edit/angular-uwpwya?file=src%2Fapp%2Fapp.component.html