我有下面的代码,将所有按钮(有 10 个)着色为灰色,以清除任何先前着色的按钮,然后将所选按钮着色为蓝色。基本上充当当前选择哪个按钮的指示器。我注意到代码现在需要一些时间才能运行这个修饰性的添加,我想知道是否有任何方法可以重写它以运行得更快?
感谢您的帮助,如果我可以提供更多详细信息,请告诉我
'
' all_days Macro
'change all buttons to grey first
ActiveSheet.Shapes.Range(Array("Rectangle: Rounded Corners 17", _
"Rectangle: Rounded Corners 12", "Rectangle: Rounded Corners 11")).Select
With Selection.ShapeRange.Fill
.Visible = msoTrue
.ForeColor.ObjectThemeColor = msoThemeColorBackground1
.ForeColor.TintAndShade = 0
.ForeColor.Brightness = -0.5
.Transparency = 0
.Solid
End With
'change selected button to blue
ActiveSheet.Shapes.Range(Array("Rectangle: Rounded Corners 12")).Select
With Selection.ShapeRange.Fill
.Visible = msoTrue
.ForeColor.ObjectThemeColor = msoThemeColorAccent1
.ForeColor.TintAndShade = 0
.ForeColor.Brightness = -0.25
.Transparency = 0
.Solid
End With
ActiveSheet.Range("$A$1:$X$740").AutoFilter Field:=12
ActiveSheet.Range("$A$1:$X$100000").AutoFilter Field:=17
End Sub```
Sub HighlightClickedShape()
Dim ShapeNames() As Variant
ShapeNames = Array("Rectangle: Rounded Corners 17", _
"Rectangle: Rounded Corners 12", "Rectangle: Rounded Corners 11")
Dim ws As Worksheet: Set ws = ActiveSheet ' improve!
Dim shprg As ShapeRange: Set shprg = ws.shapes.Range(ShapeNames)
ResetShapeRange shprg
Dim shp As Shape
On Error Resume Next
Set shp = shprg(Application.Caller)
On Error GoTo 0
If shp Is Nothing Then
MsgBox "This only works when clicking on one of the following shapes:" _
& vbLf & vbLf & Join(ShapeNames, vbLf), vbCritical
Exit Sub
End If
HighlightShape shp
End Sub
Sub ResetShapeRange(ByVal shprg As ShapeRange)
With shprg.Fill.ForeColor
.ObjectThemeColor = msoThemeColorBackground1
.Brightness = -0.5
End With
End Sub
Sub HighlightShape(ByVal shp As Shape)
With shp.Fill.ForeColor
.ObjectThemeColor = msoThemeColorAccent1
.Brightness = -0.25
End With
End Sub
我怀疑
Select
正在减慢这个过程,而且根本没有必要。通常,宏记录器创建的代码需要简化,尤其是永远不需要select某些东西。
我创建了一个包含近 100 个形状的工作表,并且以下代码可以立即运行(我的电脑已经有 6 年历史了……)。它循环遍历工作表的所有形状,通过测试形状的名称来检查形状是否应该着色。该检查被外包给一个私有函数,以使代码更具可读性 - 只需调整那里的 if 语句即可。如果你想给纸张的所有形状着色,你可以让函数在任何情况下返回 True,不需要检查名称。
在我的版本中,例程使用
Application.Caller
来查找单击以将其涂成蓝色的形状 - 因此您可以对所有形状使用相同的例程。
Sub shapes()
Dim ws As Worksheet, sh As Shape
Set ws = ActiveSheet
For Each sh In ws.shapes
If isButtonShape(sh) Then
sh.Fill.ForeColor.ObjectThemeColor = msoThemeColorBackground2
End If
Next
On Error Resume Next
Set sh = Nothing
Set sh = ws.shapes(Application.Caller)
On Error GoTo 0
If Not sh Is Nothing Then
If isButtonShape(sh) Then
sh.Fill.ForeColor.ObjectThemeColor = msoThemeColorAccent1
sh.Fill.ForeColor.TintAndShade = 0
End If
End If
End Sub
Private Function isButtonShape(sh As Shape) As Boolean
isButtonShape = (sh.Name = "Rectangle: Rounded Corners 17" _
Or sh.Name = "Rectangle: Rounded Corners 12" _
Or sh.Name = "Rectangle: Rounded Corners 11")
End Function
这是我最终使用的代码
'change all buttons to grey first
Dim shapenames() As Variant
Dim ws As Worksheet: Set ws = ActiveSheet
shapenames = Array("Rectangle: Rounded Corners 17", "Rectangle: Rounded Corners 12", "Rectangle: Rounded Corners 11")
Dim shprg As ShapeRange: Set shprg = ActiveSheet.shapes.Range(shapenames)
With shprg.Fill.ForeColor
.ObjectThemeColor = msoThemeColorBackground1
.Brightness = -0.5
End With
'change selected button to blue
Dim shapename() As Variant
shapename = Array("Rectangle: Rounded Corners 12")
Set shprg = ActiveSheet.shapes.Range(shapename)
With shprg.Fill.ForeColor
.ObjectThemeColor = msoThemeColorAccent1
End With