我得到一个
ORA-00923:在预期位置未找到 FROM 关键字
我认为它来自于尝试解析
APEX_ITEM.TEXT_FROM_LOV
。
它们是使用
APEX_ITEM.TEXT_FROM_LOV
解析 dbms_sql.parse
的方法吗?以下是生成可供解析的 SQL 查询的部分代码:
DECLARE
report_columns VARCHAR2(32767);
column_formating VARCHAR(225) := CHR(10)||CHR(9); --next line and tab
BEGIN
SELECT LISTAGG(column_alias || column_formating, ', ')
WITHIN GROUP(ORDER BY display_sequence)
INTO report_columns
FROM (SELECT CASE
WHEN REGEXP_COUNT(column_alias, CHR(32), 1, 'c') > 0 AND
column_alias NOT LIKE '%APEX_ITEM.TEXT_FROM_LOV%' THEN
'"' || column_alias || '"'
ELSE
column_alias
END column_alias,
display_sequence
FROM (SELECT CASE
WHEN named_list_of_values IS NOT NULL THEN
'APEX_ITEM.TEXT_FROM_LOV( p_value => ' ||
column_alias || ', p_lov => ''' ||
named_list_of_values || ''') ' || column_alias
ELSE
column_alias
END column_alias,
display_sequence
FROM apex_application_page_rpt_cols
WHERE application_id = p_applicaion_no
AND page_id = p_page_no
AND region_id = p_region_id
AND include_in_export = 'Yes'
ORDER BY display_sequence));
END;
或者从
APEX_APPLICATION_LOVS
获取值列表以便解码 APEX_APPLICATION_PAGE_RPT_COLS
中的列的另一种方法?在解析报告的 sql 后,我是否必须解码列?
因此生成的 sql 看起来像这样存储为 clob:
'SELECT
APEX_ITEM.TEXT_FROM_LOV(EMP_NO,'''EMP_NO_ENAME_LOV''') EMP_NO
FROM EMP'
然后将其传递给 dbms_sql.parse,因此您将得到如下结果:
EMP_NO
------
James
Jane
John
Sam
而不是
EMP_NO
------
1
2
3
4
但是我想我只能在解析sql之后才能解码值?
因此,首先从 APEX_APPLICATION_PAGE_RPT_COLS 获取region_name,然后使用 APEX_APPLICATION_LOVS,如下所示:
DECLARE
TYPE lov_array IS TABLE OF VARCHAR2(255);
l_lov lov_array := lov_array();
cursor c_region_lov is
select
named_list_of_values
from apex_application_page_rpt_cols
where named_list_of_values is not null
and include_in_export = 'Yes'
and region_name = p_region;
BEGIN
for lov_name in c_region_lov loop
l_lov.extend;
l_lov(l_lov.count) := lov_name.named_list_of_values;
end loop;
l_cursor_id := dbms_sql.open_cursor;
dbms_sql.parse(l_cursor_id, p_query, dbms_sql.native);
l_execute := DBMS_SQL.EXECUTE(l_cursor_id);
loop
if dbms_sql.fetch_rows(l_cursor_id) = 0 then exit;
end if;
for i in 1..l_col_cnt loop
l_column_values.extend;
dbms_sql.column_value(l_cursor_id, i, l_values);
if l_lov.count != 0 then
for r_lov in (select list_of_values_name from APEX_APPLICATION_LOVS where application_id = p_id and list_of_values_name member of l_lov) loop
l_column_values(l_column_values.count) := APEX_ITEM.TEXT_FROM_LOV (l_values, r_lov.list_of_values_name, l_values);
end loop;
else
l_column_values(l_column_values.count) := l_values;
end if;
end loop;
end loop;
dbms_sql.close_cursor(l_cursor_id);
END;
所以,我的假设是正确的,我只能在解析 SQL 后才能真正使用 APEX_ITEM.TEXT_FROM_LOV:
DECLARE
TYPE lov_array IS TABLE OF VARCHAR2(255);
l_lov lov_array := lov_array();
cursor c_region_lov is
select
named_list_of_values
from apex_application_page_rpt_cols
where named_list_of_values is not null
and include_in_export = 'Yes'
and region_name = p_region;
BEGIN
for lov_name in c_region_lov loop
l_lov.extend;
l_lov(l_lov.count) := lov_name.named_list_of_values;
end loop;
l_cursor_id := dbms_sql.open_cursor;
dbms_sql.parse(l_cursor_id, p_query, dbms_sql.native);
l_execute := DBMS_SQL.EXECUTE(l_cursor_id);
loop
if dbms_sql.fetch_rows(l_cursor_id) = 0 then exit;
end if;
for i in 1..l_col_cnt loop
l_column_values.extend;
dbms_sql.column_value(l_cursor_id, i, l_values);
if l_lov.count != 0 then
for r_lov in (select list_of_values_name from APEX_APPLICATION_LOVS where application_id = p_id and list_of_values_name member of l_lov) loop
l_column_values(l_column_values.count) := APEX_ITEM.TEXT_FROM_LOV (l_values, r_lov.list_of_values_name, l_values);
end loop;
else
l_column_values(l_column_values.count) := l_values;
end if;
end loop;
end loop;
dbms_sql.close_cursor(l_cursor_id);
END;