如何在if-elif语句的列表中使用数字？我不知道为什么这段代码不起作用？

Question

myList = ["shy","sociable","loud"]
print(myList)
personality = input("Pick a trait from the list: ")

if personality = 0
  print("You are a person who doesn't doesn't like talking to other people")
elif personality = 1
  print("you talk to people, but aren't really loud")
elif personality = 2
  print("You love talking to people and you are very loud")

Answer 1

1. [personality可能是string，请使用int(input(...))获得int
2. 您无法比较int与string
3. 等于运算符是==，不是=
4. 每:或if行后需要冒号elif

类似的事情可能起作用：

myList = ["shy","sociable","loud"]
print(myList)
try :
    personality = int(input("Pick a trait from the list: "))
except ValueError :
    sys.exit("Invalid input: " + str(personality))

if personality == 0 :
  print("You are a person who doesn't doesn't like talking to other people")
elif personality == 1 :
  print("you talk to people, but aren't really loud")
elif personality == 2 :
  print("You love talking to people and you are very loud")

Answer 2

有3个问题：

a）输入为字符串，您需要在int

中进行转换

b）您输入的语法错误，将是两个等号（==）

c）跳过if

结尾的：

已解决的代码：

myList = ["shy","sociable","loud"]
print(myList)
personality = int(input("Pick a trait from the list: "))

if personality == 0:
  print("You are a person who doesn't doesn't like talking to other people")
elif personality == 1:
  print("you talk to people, but aren't really loud")
elif personality == 2:
  print("You love talking to people and you are very loud")

Answer 3

Python语法：

if condition:
    Indented expressions
elif condition2:
    Other expressions
else:
    Further expressions

每个条件之后，您只是缺少colons（:）。

此外，要检查某项是否等于其他项，必须使用==。单个=执行分配。

if variable == 42:
    variable = 7

最后，您不能将整数与字符串进行比较（input ()函数返回字符串）。为此，将字符串转换为整数：

IntegerValue = int(stringFormat)

最终提示：您的控制台为您提供了有关代码错误的有用提示。听他们说。