[php内的html表单进行循环-编辑/删除按钮

Question

我正在尝试在页面上显示用户已保存到数据库并添加编辑+删除按钮的事件。我只使用html，css和php。我知道如何显示事件，但无法找出如何使按钮起作用，因为显示数据位于for循环内。我已经尽力了，但是我不知道如何使它起作用。有人可以帮我吗？我已经准备好使用全新的解决方案了：-)表单代码如下所示：

 for($i=0;$i<$count;$i++){    

     ?>
    <form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post">
         <div class="form-row align-items-center">
           <div class="col-auto">
             <label class="sr-only" for="editTime">Time</label>
             <input type="time" name="editTime" class="form-control mb-2" value="<?php echo $times[$i]; ?>">
           </div>
           <div class="col-auto">
             <label class="sr-only" for="editEvent">Event</label>
             <textarea name="editEvent" rows="2" cols="35" id="text" class="form-control"><?php echo $events[$i]; ?></textarea>
           </div>

          <div class="col-auto">
             <input type="submit" class="btn btn-success mb-2" name="btnEdit" value="Edit">
             <input type="submit" class="btn btn-danger mb-2" name="btnDel" value="Delete">

          </div>   
         </div>
    </form>
    <br>
 <?php
    array_push($casy2, $_POST["editTime"]);   

  }

以及准备好的查询：

// ready for updating 
$stmt=$mysqli->prepare("UPDATE events SET time= ?, event= ? WHERE ID = ?");
            $stmt->bind_param("ssi", $newTime,  $newEvent, $idevent);
            $stmt->execute();
            $stmt->close(); 

// ready for deleting
$stmt = $mysqli->prepare("DELETE FROM events WHERE ID = ?");      
            $stmt->bind_param("i", $ids[$i]);
            $stmt->execute();
            $stmt->close();

 //user ID
    $stmt = $mysqli->prepare("SELECT ID FROM users WHERE nick = ?");
    $stmt->bind_param("s", $_SESSION["prezdivka"]);
    $stmt->execute();
    $stmt->store_result(); 
    $stmt->bind_result($id);
    $stmt->fetch();      
    $stmt->close();

    $eventDate=$_GET["date"];
   //users events for the specific date
   $stmt = $mysqli->prepare("SELECT ID, time, event FROM events WHERE u_id = ? AND date= ? ORDER BY time ASC");
   $stmt->bind_param("is", $id, $eventDate);
   $stmt->execute();

   $result = $stmt->get_result();
    if($result->num_rows === 0) exit('No event');
    while($row = $result->fetch_assoc()) {
       $ids[] = $row['ID'];   //event ID
       $times[] = $row['time'];
       $events[] = $row['event'];
    }

    $stmt->close();

看起来像这样，我需要使按钮正常工作

Answer 1

检查是否已设置任何提交按钮。

if (isset($_POST['btnEdit'])) {
    $newTime = $_POST['editTime'];
    $newEvent = $_POST['editEvent'];
    $idevent = $_POST['eventid'];
    $stmt=$mysqli->prepare("UPDATE events SET time= ?, event= ? WHERE ID = ?");
    $stmt->bind_param("ssi", $newTime,  $newEvent, $idevent);
    $stmt->execute();
    $stmt->close(); 
} elseif (isset($_POST['btnDel')) {
    $idevent = $_POST['eventid'];
    $stmt = $mysqli->prepare("DELETE FROM events WHERE ID = ?");      
    $stmt->bind_param("i", $idevent);
    $stmt->execute();
    $stmt->close();
}

您还需要添加具有事件ID的隐藏输入：

<input type="hidden" name="eventid" value="<?php echo $ids[$i]; ?>">