XPath：选择具有特定属性名称的类名称元素

Question

具有以下XML：

<exceptions>
    <exception name="LegacyException"        msg="ERREUR DU MODULE SERVEUR">
        <context name="default"    msg="ERREUR DU MODULE SERVEUR (%1$s) : %2$s" />
    </exception>
</exceptions>

如何通过XPath选择异常名称和上下文名称？

类似这样的东西：

  String className = "LegacyException";
  String contextName= "default";       
  String query = "//exception[@name='" + className + "' and context[@name='" + contextName+ "']]";
  XPathExpression<Element> xpe = XPathFactory.instance().compile(query, Filters.element());

Answer 1

此xpath表达式

//exceptions/exception/@name
or 
//exception/@name

评估为
LegacyException
与此同时
//exceptions/exception/context/@name 
or 
//context/@name

评估为
default