如何从OpenFileDialog和FolderBrowserDialog获取文件路径?

问题描述 投票:21回答:8

嘿,我几天前开始学习C#,我正在尝试制作一个程序,复制和粘贴文件(并在需要时替换)到一个选定的目录,但我不知道如何获取目录和文件路径openfiledialog和folderbrowserdialog

我究竟做错了什么?

这是代码:

namespace filereplacer
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void direc_Click(object sender, EventArgs e)
        {
            string folderPath = "";
            FolderBrowserDialog directchoosedlg = new FolderBrowserDialog();
            if (directchoosedlg.ShowDialog() == DialogResult.OK)
            {
                folderPath = directchoosedlg.SelectedPath;
            }
        }

        private void choof_Click(object sender, EventArgs e)
        {

            OpenFileDialog choofdlog = new OpenFileDialog();
            choofdlog.Filter = "All Files (*.*)|*.*";
            choofdlog.FilterIndex = 1;

            choofdlog.Multiselect = true;
            choofdlog.ShowDialog();
        }

        private void replacebtn_Click(object sender, EventArgs e)
        {
          // This is where i'm having trouble
        }

        public static void ReplaceFile(string FileToMoveAndDelete, string FileToReplace, string BackupOfFileToReplace)
        {
            File.Replace(FileToMoveAndDelete, FileToReplace, BackupOfFileToReplace, false);
        }
    }
c# openfiledialog folderbrowserdialog
8个回答
40
投票

对于OpenFileDialog

OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;

if (choofdlog.ShowDialog() == DialogResult.OK)    
{     
    string sFileName = choofdlog.FileName; 
    string[] arrAllFiles = choofdlog.FileNames; //used when Multiselect = true           
}

对于FolderBrowserDialog

FolderBrowserDialog fbd = new FolderBrowserDialog();
fbd.Description = "Custom Description"; 

if (fbd.ShowDialog() == DialogResult.OK)
{
    string sSelectedPath = fbd.SelectedPath;
}

要访问selected folderselected file name,您可以在类级别声明两个字符串。

namespace filereplacer
{
   public partial class Form1 : Form
   {
      string sSelectedFile;
      string sSelectedFolder;

      public Form1()
      {
         InitializeComponent();
      }

      private void direc_Click(object sender, EventArgs e)
      {
         FolderBrowserDialog fbd = new FolderBrowserDialog();
         //fbd.Description = "Custom Description"; //not mandatory

         if (fbd.ShowDialog() == DialogResult.OK)      
               sSelectedFolder = fbd.SelectedPath;
         else
               sSelectedFolder = string.Empty;    
      }

      private void choof_Click(object sender, EventArgs e)
      {
         OpenFileDialog choofdlog = new OpenFileDialog();
         choofdlog.Filter = "All Files (*.*)|*.*";
         choofdlog.FilterIndex = 1;
         choofdlog.Multiselect = true;

         if (choofdlog.ShowDialog() == DialogResult.OK)                 
             sSelectedFile = choofdlog.FileName;            
         else
             sSelectedFile = string.Empty;       
      }

      private void replacebtn_Click(object sender, EventArgs e)
      {
          if(sSelectedFolder != string.Empty && sSelectedFile != string.Empty)
          {
               //use selected folder path and file path
          }
      }
      ....
}

注意:

由于你保留了choofdlog.Multiselect=true;,这意味着你可以在OpenFileDialog()中选择多个文件(通过按ctrl键并单击鼠标左键进行选择)。

在这种情况下,您可以在string[]中获取所有选定的文件:

在班级:

string[] arrAllFiles;

找到这一行(当Multiselect=true此行仅给出第一个文件时):

sSelectedFile = choofdlog.FileName; 

要获取所有文件,请使用:

arrAllFiles = choofdlog.FileNames; //this line gives array of all selected files

3
投票

你可以将Path存储到字符串变量中

string s = choofdlog.FileName;

3
投票

使用PathSystem.IO类。它包含用于操作文件路径的有用调用,包括执行所需操作的GetDirectoryName,返回文件路径的目录部分。

用法很简单。

string directoryPath = System.IO.Path.GetDirectoryName(choofdlog.FileName);

2
投票

要获取所选文件的完整文件路径,则需要对一个文件使用FileName属性,对多个文件使用FileNames属性。

var file = choofdlog.FileName; // for one file

或多个文件

var files = choofdlog.FileNames; // for multiple files.

要获取文件的目录,可以使用Path.GetDirectoryName 这是Jon Keet的answer关于从路径获取目录的类似问题


1
投票

choofdlog返回之后,你的FileName拥有包含文件路径的FileNamesShowDialog()(用于多选)。


1
投票

将此类创建为Extension:

public static class Extensiones
{
    public static string FolderName(this OpenFileDialog ofd)
    {
            string resp = "";
            resp = ofd.FileName.Substring(0, 3);
            var final = ofd.FileName.Substring(3);
            var info = final.Split('\\');
            for (int i = 0; i < info.Length - 1; i++)
            {
                resp += info[i] + "\\";
            }
            return resp;
    }
}

然后,您可以这样使用:

        //ofdSource is an OpenFileDialog 
        if (ofdSource.ShowDialog(this) == DialogResult.OK)
        {
            MessageBox.Show(ofdSource.FolderName());
        }

1
投票

一个原始的快速修复工作。

如果你只使用OpenFileDialog,你可以捕获FileNameSafeFileName,然后减去获取文件夹路径:

exampleFileName = ofd.SafeFileName;
exampleFileNameFull = ofd.FileName;
exampleFileNameFolder = ofd.FileNameFull.Replace(ofd.FileName, "");

0
投票

我很抱歉,如果我迟到在这里回复,但我只是认为我应该为OpenDialog提供一个更简单的解决方案。

OpenDialog ofd = new OpenDialog();
var fullPathIncludingFileName = ofd.Filename; //returns the full path including the filename
var fullPathExcludingFileName = ofd.Filename.Replace(ofd.SafeFileName, "");//will remove the filename from the full path

我之前还没有使用过FolderBrowserDialog所以我会相信我的同伴们对此有所了解。我希望这有帮助。

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