ActionScript 2.0上的基于瓷砖的移动（adobe flash cs6）

Question

所以我遇到了这个问题，我不知道如何为动作脚本2.0在4个方向（NSWE）上进行基于代码块的移动。

我有此代码，但它是动态移动，它使char沿所有8个方向（NW，NE，SW，SE N，S，W，E）移动。目标是将移动限制在仅基于四个方向（NSEW）的图块基础上]

 onClipEvent(enterFrame)
{
    speed=5;
    if(Key.isDown(Key.RIGHT))
    {
        this.gotoAndStop(4);
        this._x+=speed;
    }
    if(Key.isDown(Key.LEFT))
    {
        this.gotoAndStop(3);
        this._x-=speed;
    }
    if(Key.isDown(Key.UP))
    {
        this.gotoAndStop(1);
        this._y-=speed;
    }
    if(Key.isDown(Key.DOWN))
    {
        this.gotoAndStop(2);
        this._y+=speed;
    }
}

Answer 1

最简单明了的方法是沿着X轴OR沿着Y轴移动该对象，一次仅移动一个，不能同时移动两个。

onClipEvent(enterFrame)
{
    speed = 5;

    dx = 0;
    dy = 0;

    // Figure out the complete picture of keyboard input.

    if (Key.isDown(Key.RIGHT))
    {
        dx += speed;
    }

    if (Key.isDown(Key.LEFT))
    {
        dx -= speed;
    }

    if (Key.isDown(Key.UP))
    {
        dy -= speed;
    }

    if (Key.isDown(Key.DOWN))
    {
        dy += speed;
    }

    if (dx != 0)
    {
        // Move along X-axis if LEFT or RIGHT pressed.
        // Ignore if it is none or both of them.

        this._x += dx;

        if (dx > 0)
        {
            this.gotoAndStop(4);
        }
        else
        {
            this.gotoAndStop(3);
        }
    }
    else if (dy != 0)
    {
        // Ignore if X-axis motion is already applied.
        // Move along Y-axis if UP or DOWN pressed.
        // Ignore if it is none or both of them.

        this._y += dy;

        if (dy > 0)
        {
            this.gotoAndStop(2);
        }
        else
        {
            this.gotoAndStop(1);
        }
    }
}