如何使用flask在python脚本中处理上传的csv文件

问题描述 投票:-1回答:1

如何通过给python脚本提供文件路径并下载处理过的文件来处理上传的文件? 代码

@app.route("/upload", methods=['POST'])
def upload():
    target = os.path.join(APP__ROOT, 'data/')
    print(target)
    if not os.path.isdir(target):
        os.mkdir(target)
    for file in request.files.getlist("file"):
        filename = file.filename
        print(filename)
        destination = "/".join([target, filename])
        print(destination)
        file.save(destination)
    return render_template("downloads.html")
python flask pycharm
1个回答
0
投票

您需要返回该文件。

response = app.make_response(file)
response.headers["Content-Disposition"] = "attachment; filename=yourfile.csv"
return response
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