ng-select:如何选择标签相同但对象不同的多个项目

问题描述 投票:0回答:1

我正在尝试在ng-select下拉菜单中修补多个选定项。我没有指定任何bindValue,因此这些项目应按对象进行绑定(如https://www.npmjs.com/package/@ng-select/ng-select所指定)

但是在尝试执行此操作时,不会根据对象而是根据显示的标签来选择项目。也只有第一个标签被选中。

示例:app.component.html

<form [formGroup]="group">
    <div class="form-group" formGroupName="school">
        <ng-select labelForId="school" placeholder="Select school" [items]="schools" formControlName="code"
            bindLabel="displayLabel" multiple="true" groupBy="city">
        </ng-select>
    </div>
</form>

app.component.ts

import { Component, OnInit } from '@angular/core';
import { FormBuilder, FormGroup, FormControl, Validators } from '@angular/forms';

@Component({
  selector: 'my-app',
  templateUrl: './app.component.html',
  styleUrls: ['./app.component.css']
})
export class AppComponent implements OnInit {
  group: FormGroup;
  schools = [];
  constructor(private fb: FormBuilder) { }

  ngOnInit() {
    this.initSchools();
    const formModel = {
      school: new FormGroup({
        code: new FormControl(null, Validators.required)
      })
    }
    this.group = this.fb.group(formModel);
    this.group.patchValue({
      school: {
        code:
          [
            {
              schoolId: 'SC003',
              displayLabel: 'Test-3 school',
              city: "City1"
            },
            {
              schoolId: 'SC005',
              displayLabel: 'Test-3 school',
              city: "City5"
            }
          ]
      }
    });
  }

  initSchools() {
    this.schools.push(
      {
        schoolId: 'SC001',
        displayLabel: 'Test-1 school',
        city: "City1"
      },
      {
        schoolId: 'SC002',
        displayLabel: 'Test-2 school',
        city: "City2"
      },
      {
        schoolId: 'SC003',
        displayLabel: 'Test-3 school',
        city: "City3"
      },
      {
        schoolId: 'SC004',
        displayLabel: 'Test-4 school',
        city: "City4"
      },
      {
        schoolId: 'SC005',
        displayLabel: 'Test-3 school',
        city: "City5"
      }
    );
  }
}

在上面的示例中,仅项目的对象

    {
      schoolId: 'SC003',
      displayLabel: 'Test-3 school',
      city: "City1"
    },

被选中,

并且下面的项目没有

    {
      schoolId: 'SC005',
      displayLabel: 'Test-3 school',
      city: "City5"
    }

应该采用什么方式来使两个项目都在下拉菜单中被选中(并提供唯一的对象)。这里有什么遗漏的东西吗?其他实现此目的的方法。

有示例在这里运行:https://stackblitz.com/edit/angular-szel64?file=src%2Fapp%2Fapp.component.ts

angular dropdown angular-reactive-forms multi-select angular-ngselect
1个回答
0
投票

发现ng-select有一个compareWith选项,可让您定义一个比较对象的函数。您可以使用此对象绑定对象,并根据compareWith选项提供的功能对其进行选择。

下面是我的更改,以防有人陷入同一问题

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