我,使用Graphaware Neo4j-php-OGM。我想访问二级关系。我无法看到让它发挥作用。我究竟做错了什么?
我正在尝试执行以下操作:
public function allowToContinue($userUuid, $permissionUuid)
{
$userRepo = $this->entityManager->getRepository(User::class);
$permRoleRepo = $this->entityManager->getRepository(PermRole::class);
$permissionRepo = $this->entityManager->getRepository(Permission::class);
$user = $userRepo->findOneBy(['uuid' => $userUuid]);
$permission = $permissionRepo->findOneBy(['uuid' => $permissionUuid]);
$allowed = false;
foreach ($user->getPermrole() as $userRole)
{
var_dump($userRole);
$role = $permRoleRepo->findOneBy(['uuid' => $userRole->getUuid()]);
var_dump($role);
foreach ($role->getPermissions() as $perm)
{
var_dump($perm->getUuid());
if($perm->getUuid() === $permissionUuid){
$allowed = true;
}
}
}
return $allowed;
}
堆栈跟踪:
Error:
Call to a member function isCollection() on null
at vendor/graphaware/neo4j-php-ogm/src/Hydrator/EntityHydrator.php:107
at GraphAware\Neo4j\OGM\Hydrator\EntityHydrator->hydrateSimpleRelationshipCollection('permissions', object(Result), object(neo4j_ogm_proxy_App_Entity_Generic_PermRole))
(vendor/graphaware/neo4j-php-ogm/src/Persisters/BasicEntityPersister.php:104)
at GraphAware\Neo4j\OGM\Persisters\BasicEntityPersister->getSimpleRelationshipCollection('permissions', object(neo4j_ogm_proxy_App_Entity_Generic_PermRole))
(vendor/graphaware/neo4j-php-ogm/src/Proxy/NodeCollectionInitializer.php:22)
at GraphAware\Neo4j\OGM\Proxy\NodeCollectionInitializer->initialize(object(Node), object(neo4j_ogm_proxy_App_Entity_Generic_PermRole))
(vendor/graphaware/neo4j-php-ogm/src/Proxy/LazyCollection.php:52)
at GraphAware\Neo4j\OGM\Proxy\LazyCollection->doInitialize()
(vendor/doctrine/collections/lib/Doctrine/Common/Collections/AbstractLazyCollection.php:332)
at Doctrine\Common\Collections\AbstractLazyCollection->initialize()
(vendor/doctrine/collections/lib/Doctrine/Common/Collections/AbstractLazyCollection.php:274)
at Doctrine\Common\Collections\AbstractLazyCollection->getIterator()
(src/Security/RoleChecker.php:45)
at App\Security\RoleChecker->allowToContinue('8d88d920-5ab0-11e8-a371-001c42dff143', 'd93370b0-585d-11e8-a371-001c42dff143')
(src/Controller/Generic/UserController.php:146)
at App\Controller\Generic\UserController->destroy('c34f1380-5ab5-11e8-a371-001c42dff143')
(vendor/symfony/http-kernel/HttpKernel.php:149)
at Symfony\Component\HttpKernel\HttpKernel->handleRaw(object(Request), 1)
(vendor/symfony/http-kernel/HttpKernel.php:66)
at Symfony\Component\HttpKernel\HttpKernel->handle(object(Request), 1, true)
(vendor/symfony/http-kernel/Kernel.php:188)
at Symfony\Component\HttpKernel\Kernel->handle(object(Request))
(public/index.php:37)
它会在第二个foreach循环上引发错误:
foreach ($role->getPermissions() as $perm)
这很奇怪,第一次正确工作而不是第二次。此外,再次获取对象后,确保。没有它,它会抛出完全相同的通知。提前致谢!
所有代码都在github:https://github.com/djkevino/Support4Neo
老实说,这段代码非常困惑。 var_dump() die()
中的destroy()
内容...另外,我花了一段时间才意识到我们正在讨论库中的代码,而不是与此库交互的代码。
你能避免这样的问题吗?
//add this next line
if (!is_iterable($user->getPermrole())) continue;
foreach ($role->getPermissions() as $perm)
如果您不使用PHP 7.1或更高版本,您只需检查返回值is_null
或测试instance of \Traversable
和is_array
...
is_array($foo) || (is_object($foo) && ($foo instanceof \Traversable ));
如我的评论中所述,不确定没有“权限”的角色是否被视为有效状态。
null
结果。因此,在执行内部null
循环之前,请确保结果不是foreach
。$allowed
变量。一旦发现匹配,内部foreach
循环可以立即返回true
,避免不必要的处理。也就是说,试试这个:
public function allowToContinue($userUuid, $permissionUuid) {
$userRepo = $this->entityManager->getRepository(User::class);
$permRoleRepo = $this->entityManager->getRepository(PermRole::class);
$permissionRepo = $this->entityManager->getRepository(Permission::class);
$user = $userRepo->findOneBy(['uuid' => $userUuid]);
$permission = $permissionRepo->findOneBy(['uuid' => $permissionUuid]);
foreach ($user->getPermrole() as $userRole) {
var_dump($userRole);
$role = $permRoleRepo->findOneBy(['uuid' => $userRole->getUuid()]);
var_dump($role);
$rolePerms = $role->getPermissions();
if (!is_null($rolePerms)) {
foreach ($rolePerms as $perm) {
var_dump($perm->getUuid());
if ($perm->getUuid() === $permissionUuid) {
return true;
}
}
}
}
return false;
}