我有这样的对象,其中'id'是唯一的。我需要从小于ES5的任何版本的JavaScript中的对象数组中删除重复项。我需要根据ID字段进行比较,并删除其重复项。
示例:
Object = [
{id: id_one, value: value_one, label: ABC},
{id: id_one, value: value_one, label: ABC},
{id: id_three, value: value_three, label: ABX},
{id: id_two, value: value_two, label: ABY},
{id: id_four, value: value_four, label: ABD}
];
输出:
result = [
{id: id_one, value: value_one, label: ABC},
{id: id_three, value: value_three, label: ABX},
{id: id_two, value: value_two, label: ABY},
{id: id_four, value: value_four, label: ABD}
];
我尝试过这样的逻辑,
function getDistValues(object) {
var distObject = [];
var tempIndex = [];
var length = object.length;
for (var i = 0; i < length; i++) {
tempIndex.push(object[i].id);
if (tempIndex.indexOf(object[i].id) === -1 || i === 0) {
distObject.push(object[i]);
}
}
return distObject;
}
它只是给第一个对象。我尝试过映射ID并进行比较,但没有用。
任何帮助都会对我有用。
这是因为您总是将id添加到tempIndex
数组,因此它总是认为当前的ID是重复的。试试:
function getDistValues(object) {
var distObject = [];
var tempIndex = [];
var length = object.length;
for (var i = 0; i < length; i++) {
if (tempIndex.indexOf(object[i].id) === -1 || i === 0) {
tempIndex.push(object[i].id);
distObject.push(object[i]);
}
}
return distObject;
}
这里是使用reduce和object的解决方案
const input = [
{id: 'id_one', value: 'value_one', label: 'ABC'},
{id: 'id_one', value: 'value_one', label: 'ABC'},
{id: 'id_three', value: 'value_three', label: 'ABX'},
{id: 'id_two', value: 'value_two', label: 'ABY'},
{id: 'id_four', value: 'value_four', label: 'ABD'}
]
const output = Object.values(
input.reduce((memo, curr) => {
memo[curr.id] = curr
return memo
}, {})
)
console.log(output)
您正在将项目添加到tempIndex
数组*,然后检查它们是否在那里。由于您总是添加每一项,因此隐含的是,当您进行检查时,该项已经存在。
您必须将其取反-检查项目是否存在然后将其添加到tempIndex
var data = [
{id: "id_one", value: "value_one", label: "ABC"},
{id: "id_one", value: "value_one", label: "ABC"},
{id: "id_three", value: "value_three", label: "ABX"},
{id: "id_two", value: "value_two", label: "ABY"},
{id: "id_four", value: "value_four", label: "ABD"}
];
function getDistValues(object) {
var distObject = [];
var tempIndex = [];
var length = object.length;
for (var i = 0; i < length; i++) {
//check first
var exists = tempIndex.indexOf(object[i].id) === -1;
if (exists) {
tempIndex.push(object[i].id);
//add later
distObject.push(object[i]);
}
}
return distObject;
}
var result = getDistValues(data);
console.log(result);
您可以将Set
作为Set
属性,如果id
未在集合中,则进行过滤。
id
var array = [{ id: 'id_one', value: 'value_one', label: 'ABC' }, { id: 'id_one', value: 'value_one', label: 'ABC' }, { id: 'id_three', value: 'value_three', label: 'ABX' }, { id: 'id_two', value: 'value_two', label: 'ABY' }, { id: 'id_four', value: 'value_four', label: 'ABD' }],
unique = array.filter((ids => ({ id }) => !ids.has(id) && ids.add(id))(new Set));
console.log(unique);