Laravel动态下拉列表获取数据问题

Question

我想在插入时根据user_types列出用户，所以我创建了两个表，每个表都有连接。每个模型PHP文件都有一个关系函数。并且我创建了jquery代码并创建了控制器功能，但是它不起作用，我不知道我在哪里犯了错误，请帮助我解决此问题。我附加了我编写的所有代码以及数据库。

用户类型数据库

用户数据库表

UserType ID和用户表usty_id具有连接

UserType模型

<?php

namespace Asset_Management_System;

use Illuminate\Database\Eloquent\Model;

class UserType extends Model
{
    public function userpermission()
    {
        return $this->hasMany('Asset_Management_System\UserPermission');
    }

    public function user()
    {
        return $this->hasMany('Asset_Management_System\User');
    }
}

用户模型

class User extends Authenticatable
    {

        public function usertype()
        {
            return $this->belongsTo('Asset_Management_System\UserType','usty_id');
        }
}

插入表格

<div class="form-group">
                                    <label>User Type</label>
                                    <select class="form-control select2" style="width: 100%;" id="ust_id" name="ust_id">
                                        <option selected="selected">Select User Type</option>
                                        @foreach($UserType as $ust)
                                            <option value="{{$ust->id}}">{{$ust->usty_name}}</option>
                                        @endforeach
                                    </select>
                                </div>

                                <div class="form-group">
                                    <label>User</label>
                                    <select class="form-control select2" style="width: 100%;" id="user_id" name="user_id">
                                        <option selected="selected">Select User</option>
                                        @foreach($User as $us)
                                            <option value="{{$us->id}}">{{$us->us_fname}} {{$us->us_lname}}</option>
                                        @endforeach
                                    </select>
                                </div>

Controller

public function show(Request $request)
    {
        //echo $id;
        if (!$request->usty_id) {
            $html = '<option value="">'.trans('global.pleaseSelect').'</option>';
        } else {
            $html = '';
            $user = User::where('usty_id', $request->usty_id)->get();
            foreach ($user as $us) {
                $html .= '<option value="'.$us->id.'">'.$us->us_fname.' '.$us->us_lname.'</option>';
            }
        }

        return response()->json(['html' => $html]);

    }

和Jquery

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

    <script type="text/javascript">
        $("#ust_id").change(function(){
            $.ajax({
                url: "{{ route('WorkRequest.show') }}?usty_id=" + $(this).val(),
                method: 'GET',
                success: function(data) {
                    $('#user_id').html(data.html);
                }
            });
        });
    </script>

路线

Route::get('WorkRequest/show', 'WorkRequestController@show')->name('WorkRequest/show');

这是我进入表格时遇到的错误

缺少[Route：WorkRequest.show] [URI：WorkRequest / {WorkRequest}]所需的参数。 （查看：C：\ xampp \ htdocs \ Asset_Management_Laravel \ resources \ views \ layouts \ main.blade.php）

请帮助我解决此问题

Answer 1

此代码运行正常

<script type="text/javascript">

            $(document).ready(function(){

                // Department Change
                $('#ust_id').change(function(){

                    // Department id
                    var id = $(this).val();

                    // Empty the dropdown
                    $('#user_id').find('option').not(':first').remove();

                    // AJAX request
                    $.ajax({
                        url: "{{ route('WorkRequest/show') }}?usty_id=" + id,
                        type: 'get',
                        dataType: 'json',
                        success: function(response){

                            //alert(response);

                            $('#user_id').html(response.html);

                        }
                    });
                });

            });


        </script>

public function show(Request $request)
    {
        //echo $id;

            $html = '';
            $user = User::where('usty_id', $request->usty_id)->get();
            foreach ($user as $us)
            {
                $html .= '<option value="'.$us->id.'">'.$us->us_fname.' '.$us->us_lname.'</option>';
            }


        return response()->json(['html' => $html]);

    }

Answer 2

用此Route::post('workRequest/get_options','WorkRequestController@getOptions')->name('workRequest.options');替换在路径上方，并放置在route :: resource（）路径上方

和下面的ajax代码

   $("#ust_id").change(function(){
        let parameter = {'usty_id': $(this).val()};
        $.ajax({
            url: "{{ route('workRequest.options') }}",
            method: 'POST',
            data: parameter,
            success: function(data) {
                $('#user_id').html(data.html);
            }
        });
    });

添加此Controller方法以获取选项

public function getOptions(Request $request)
    {
        if (!$request->usty_id) {
            $html = '<option value="">'.trans('global.pleaseSelect').'</option>';
        } else {
            $html = '';
            $user = User::where('usty_id', $request->usty_id)->get();
            foreach ($user as $us) {
                $html .= '<option value="'.$us->id.'">'.$us->us_fname.' '.$us->us_lname.'</option>';
            }
        }

        return response()->json(['html' => $html]);

    }