Tomcat 和 Java Servlet 出现 404

问题描述 投票:0回答:1

问题: 我正在尝试使用 html 表单向我的 java servlet 发出 get 请求,但收到 404 错误。

我尝试将操作标记的路径更改为 /Main 和 /Assignment9Test/Main,但都不起作用。当我运行 Java servlet 时,它显示为 http://localhost:8080/Assignment9Test/Main3.java 并在浏览器中显示 servlet 代码

我试图到达的端点 - http://localhost:8080/Assignment9Test/Main3?param1=1¶m2=2¶m3=3

错误 - HTTP 状态 404 – 未找到

文件结构

Main.html

"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; ">
<title>A Sample form using GET</title>
</head>
<body bgcolor="#fdf5e6">
<center>
<h2>Collecting Three Parameters</h2>
<form action="http://localhost:8080/Assignment9Test/Main3" method="get">
First Parameter&nbsp;&nbsp;&nbsp;&nbsp;:
<input type="text" name="param1"><br>
Second Parameter: <input type="text" name="param2"><br>
Third Parameter&nbsp;&nbsp;&nbsp;&nbsp;:
<input type="text" name="param3"><br>
<input type="submit" value="Submit">
</form>
</center>
</body>
</html>

web.xml

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd" id="WebApp_ID" version="4.0">
  <display-name>Assignment9Test</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.jsp</welcome-file>
    <welcome-file>default.htm</welcome-file>
  </welcome-file-list>
</web-app>

Main.java

import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/Main3")
public class Main extends HttpServlet {
static final long serialVersionUID = 1L;
public Main() {
    super();
}
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
//String title = "Reading Three Request Parameters";
//out.println(
//"<html>\n" +
//"<head><title>" + title + "</title></head>\n" +
//"<body bgcolor=\"#ff5e6\">\n" +
//"<h1 align=\"center\">" + title + "</h1>\n" +
//"<ul>\n" +
//" <li><b>param1</b>: " + request.getParameter("param1") + "\n" +
//" <li><b>param2</b>: " + request.getParameter("param2") + "\n" +
//" <li><b>param3</b>: " + request.getParameter("param3") + "\n" +
//"</ul>\n" +
//"</body></html>");
}
}
java html servlets tomcat9
1个回答
0
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您的

<form>
标签属性值错误。在操作属性中,您应该使用
action="Main3"

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