eventsource.onmessage不被调用-flask应用程序

问题描述 投票:0回答:1

我一直在开发flask应用程序,并在其中尝试实现SSE。检查下面的代码:

index.py

@app.route('/stream', methods=['GET'])
@cross_origin()
def stream():
    def listenstream():
        print("listening")
        displaytext =  { 'requestdata':  'Sampledata', 'responsedata' : 'Sample Data'}
        displaytext=json.dumps(displaytext)
        yield 'event: message\n'
        yield 'data : '+displaytext+'\n\n'
        time.sleep(1.5)

    return Response(response=listenstream(),status=200,mimetype="text/plain",content_type='text/event-stream')

custom.js

var eventSource = new EventSource("/stream");

eventSource.onmessage = function (e) {
   console.log("Onmessage"+e)
}


eventSource.onerror = function (e) {
   console.log("Onerror"+JSON.stringify(e))
}

eventSource.onopen = function (e) {
   console.log("Onopen"+JSON.stringify(e))
}

此处eventSource.onerror => {“ isTrusted”:true},eventSource.onopen => {“ isTrusted”:true},但未调用eventSource.onmessage。我在js文件中尝试过addEventListener:

var eventSource = new EventSource("/stream");
eventSource.addEventListener('message', (e) => {

console.log("Received update")
})

如果我渲染链接'http://localhost:5000/stream',它将给出:

事件:消息

数据:{“ requestdata”:“ Sampledata”,“ responsedata”:“ Sampledata”}

但是我需要链接'http://localhost:5000'上的数据。这是正确的做法吗?

将不胜感激:)

flask eventsource
1个回答
0
投票

更新后为我解决了这个问题:

index.py

     yield "event: {0}\ndata: {1}\n\n".format("listen",displaytext)

return Response(listenstream(), mimetype="text/event-stream")

custom.js

var eventSource = new EventSource("/stream");
eventSource.addEventListener('listen', function(e){ 

//Code here
},false);
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