无法从架构stiching中的另一个schema.graphql文件中的其他schema.graphql文件访问共享架构

问题描述 投票:1回答:1

我在userSchema.graphql文件中有用户模式;

  id: String!
  userName: String!
  email: String!
  password: String!
}

我有不同的schema.graphql文件用于登录和注册

我无法访问登录/注册架构中的用户架构

type Query{
    hi: String!
}
type Mutation {
    register( userName: String!, email: String!, password: String! ): User
}

我正在使用graphql工具中的模式stiching并合并来自merge-graphql-schema包的typeDefs和resolver

import "graphql-import-node";
import { GraphQLSchema } from "graphql";
import { mergeResolvers, mergeTypes } from "merge-graphql-schemas";
import * as userSchema from './modules/auth/shared/schema.graphql'
import * as registerTypedefs from "./modules/auth/register/schema.graphql";
import registerResolver from "./modules/auth/register/registerResolver";

import * as todoTypedefs from "./modules/todo/schema.graphql";
import todoResolver from "./modules/todo/todoResolver";

import { makeExecutableSchema } from "graphql-tools";

const schema: GraphQLSchema = makeExecutableSchema({
  typeDefs: mergeTypes([userSchema, registerTypedefs, todoTypedefs], { all: true }),
  resolvers: mergeResolvers([registerResolver, todoResolver])
});
export default schema;

我收到了错误

Error: Field register: Couldn't find type User in any of the schemas.
    at collectNode (E:\graphql\express-apollo-server\node_modules\graphql-import\src\definition.ts:154:15)
    at E:\graphql\express-apollo-server\node_modules\graphql-import\src\definition.ts:135:7
    at Array.forEach (<anonymous>)

编辑我使用了'merge-graphql-schemas'中的fileLoader,它运行得很好

import { mergeResolvers, mergeTypes, fileLoader } from "merge-graphql-schemas";


const typesArray = fileLoader(path.join(__dirname, './modules/**/*.graphql'), { recursive: true })
const schema: GraphQLSchema = makeExecutableSchema({
  typeDefs: mergeTypes(typesArray, { all: true }),
  resolvers: mergeResolvers([registerResolver, loginRegister, todoResolver, storyResolver])
});
typescript graphql apollo-server graphql-tools
1个回答
1
投票

我在我的项目中使用了require-graphql-file和lodash merge,同样的场景对我有用。

import requireGraphQLFile from 'require-graphql-file';
import { merge } from 'lodash';

const $userSchema = requireGraphQLFile('./schema/yourFolder/userSchema.graphql');
const $registerTypedefs= requireGraphQLFile('./schema/yourFolder/register.graphql');

import registerResolver from "./modules/auth/register/registerResolver";
import todoResolver from "./modules/todo/todoResolver";

const schema: GraphQLSchema = makeExecutableSchema({
   typeDefs: [$userSchema, 
              $registerTypedefs,
              todoTypedefs
             ],              
   resolvers: merge(registerResolver, todoResolver)
});

希望这会有所帮助。

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