我需要使用从关系表中的3个属性强制转换的VARRAY创建VIEW。
我尝试了很多方法,但是没有得到积极的结果。在oracle文档中也找不到解决方案。
CREATE TABLE Client (
ID_Client NUMBER(7,0),
Phone1 VARCHAR2(9),
Phone2 VARCHAR2(9),
Phone3 VARCHAR2(9),
CONSTRAINT Client_PK
PRIMARY KEY (ID_Client)
);
/
CREATE TYPE phone_vartyp IS VARRAY(3) OF VARCHAR2(9);
/
CREATE TYPE client_objtyp AS OBJECT (
ID_Client NUMBER(7,0),
Phones phone_vartyp
);
/
CREATE VIEW client_objv OF client_objtyp
WITH OBJECT IDENTIFIER (ID_Client)
AS SELECT c.ID_Client,
CAST(MULTISET(SELECT c.Phone1, c.Phone2, c.Phone3
FROM Client c) AS phone_vartyp)
FROM Client c; -- ORA-00932
/
CREATE VIEW client_objv OF client_objtyp
WITH OBJECT IDENTIFIER (ID_Client)
AS SELECT c.ID_Client,
(SELECT CAST(c.Phone1, c.Phone2, c.Phone3) AS phone_vartyp FROM Client c) as phone_vartyp
FROM Client c; -- ORA-00905
/
DROP TABLE Client;
DROP TYPE client_objtyp;
DROP TYPE phone_vartyp;
似乎您在考虑这个问题。无需使用CAST
或MULTISET
或子查询。从多个值创建VARRAY
的最简单方法就是像使用函数一样使用类型,并将所有元素作为参数传递。
以下内容似乎起作用:
CREATE OR REPLACE VIEW client_objv OF client_objtyp
WITH OBJECT IDENTIFIER (ID_Client)
AS SELECT c.ID_Client,
phone_vartyp(c.Phone1, c.Phone2, c.Phone3)
FROM Client c;