我的任务是获取一个XML文件并将其转换为新的XML,我没有使用XML文档的经验,但是我已经能够使用下面显示的代码从第一个XML文档中获取一些数据。请注意,并非所有代码都只是一个小示例而已。
XmlDocument rssXmlDoc = new XmlDocument();
// Load the RSS file from the RSS URL
rssXmlDoc.Load("https://agency.governmentjobs.com/jobfeed.cfm?agency=ocso");
// Setup name space
XmlNamespaceManager nsmgr = new XmlNamespaceManager(rssXmlDoc.NameTable);
nsmgr.AddNamespace("joblisting", "http://www.neogov.com/namespaces/JobListing");
// Parse the Items in the RSS file
XmlNodeList rssNodes = rssXmlDoc.SelectNodes("rss/channel/item/");
// Iterate through the items in the RSS file
foreach (XmlNode rssNode in rssNodes)
{
XmlNode rssSubNode = rssNode.SelectSingleNode("title");
string title = rssSubNode != null ? rssSubNode.InnerText : "";
使用此代码,我可以获得大多数元素。尝试从子元素获取数据时遇到了麻烦。无法显示的XML部分如下所示。
<joblisting:department>Supply</joblisting:department>
<guid isPermaLink="true">https://www.governmentjobs.com/careers/ocso/Jobs/2594527</guid>
<joblisting:categories>
<joblisting:category xmlns:joblisting="http://www.neogov.com/namespaces/JobListing" xmlns:atom="http://www.w3.org/2005/Atom">
<CategoryCode>ClericalDataEntry</CategoryCode>
<Category>Clerical & Data Entry</Category>
</joblisting:category>
<joblisting:category
</joblisting:categories>
但是我无法获取所有数据。如何获得以guid isPermaLink =“ true”
开头的元素的值对于Joblisting:类别,我已经使用了foreach循环来读取这些值
foreach (var item in rssSubNode.SelectNodes("joblisting:categories", nsmgr))
{
rssSubNode = rssSubNode = rssNode.SelectSingleNode("joblisting:category", nsmgr);
string category = rssSubNode != null ? rssSubNode.InnerText : "";
}
如何读取这些子元素的值?
public static void test() {
XmlDocument rssXmlDoc = new XmlDocument();
// Load the RSS file from the RSS URL
rssXmlDoc.Load("https://agency.governmentjobs.com/jobfeed.cfm?agency=ocso");
// Setup name space
XmlNamespaceManager nsmgr = new XmlNamespaceManager(rssXmlDoc.NameTable);
nsmgr.AddNamespace("joblisting", "http://www.neogov.com/namespaces/JobListing");
// Parse the Items in the RSS file
XmlNodeList rssNodes = rssXmlDoc.SelectNodes("rss/channel/item");
// Iterate through the items in the RSS file
foreach (XmlNode rssNode in rssNodes) {
var xmlnode = rssNode.SelectSingleNode("guid ");
System.Console.WriteLine("the value of guid is =>" + xmlnode.InnerText);
XmlNode rssSubNode = rssNode.SelectSingleNode("title");
string title = rssSubNode != null ? rssSubNode.InnerText : "";
}
}