我正在使用Windows工作流基础4.0,我已经在我的按钮点击事件上创建了Web应用程序,我有以下内容
Dictionary<string,object> dicobjParams=new Dictionary<string,object>();
WorkflowRuntime workflowRuntime = Application["WorkflowRuntime"] as WorkflowRuntime;
WorkflowInstance instance =workflowRuntime.CreateWorkflow(typeof(Activity1),dicobjParams);
//workflowRuntime.CreateWorkflow(typeof(Activity1), dicobjParams).Start();
workflowRuntime.WorkflowCompleted += new EventHandler<WorkflowCompletedEventArgs>(workflowRuntime_WorkflowCompleted);
instance.Start();
但我总是出现以下错误
输入工作流类型必须是活动。参数名称:workflowType
正如在this线程中提到的,我确保我使用的是4.0应用程序和工作流程。
请查看the code申请样本以便进一步了解
如果您使用的是wwf 4.0,则无法使用WorkflowRuntime,而是必须使用WorkflowApplication,如:
Dictionary<string, object> dicobjParams = new Dictionary<string, object>();
Activity workflow1 = new MyApp.Activity1();
WorkflowApplication app = new WorkflowApplication(workflow1, dicobjParams );
app.Run();
我建议你阅读:https://msdn.microsoft.com/en-us/library/ee342461.aspx