确定成员调用是否在Clang AST中是虚拟的

问题描述 投票:1回答:1

[我想编写一个通过查看C ++ AST(virtual的输出)来对-ast-dump函数调用进行计数的分析器,但是我很难确定哪些函数调用为virtual,哪些不是。这是一个示例代码:

struct A {
    A() {}
    virtual int foo() { return 0; }
};
struct B : public A {
    B() {}
    //virtual int foo() { return 3; }
};

struct C : public B {
    C() {}
    virtual int foo() { return 1; }
};

int test(C* c) { 
    return c->foo() + c->B::foo() + c->A::foo();
}

[在我的初始实现中,我只是使用virtual检查正在调用的函数是否为expr->getMethodDecl()->isVirtual(),但是(据我了解)c->B::foo()c->A::foo()中的调用实际上不是virtual,因此不足以询问被调用的函数是否为virtual

[当我从这段代码中转储AST时,我得到了test的以下树:

`-FunctionDecl 0x1d33620 <line:19:1, line:21:1> line:19:5 test 'int (C *)'
  |-ParmVarDecl 0x1d33558 <col:10, col:13> col:13 used c 'C *'
  `-CompoundStmt 0x1d339f0 <col:16, line:21:1>
    `-ReturnStmt 0x1d339e0 <line:20:5, col:47>
      `-BinaryOperator 0x1d339c0 <col:12, col:47> 'int' '+'
        |-BinaryOperator 0x1d338a8 <col:12, col:33> 'int' '+'
        | |-CXXMemberCallExpr 0x1d33778 <col:12, col:19> 'int'
        | | `-MemberExpr 0x1d33748 <col:12, col:15> '<bound member function type>' ->foo 0x1d31c80
        | |   `-ImplicitCastExpr 0x1d33730 <col:12> 'C *' <LValueToRValue>
        | |     `-DeclRefExpr 0x1d33710 <col:12> 'C *' lvalue ParmVar 0x1d33558 'c' 'C *'
        | `-CXXMemberCallExpr 0x1d33848 <col:23, col:33> 'int'
        |   `-MemberExpr 0x1d33800 <col:23, col:29> '<bound member function type>' ->foo 0x1d02400
        |     `-ImplicitCastExpr 0x1d33888 <col:23> 'A *' <UncheckedDerivedToBase (A)>
        |       `-ImplicitCastExpr 0x1d33868 <col:23> 'B *' <UncheckedDerivedToBase (B)>
        |         `-ImplicitCastExpr 0x1d337d8 <col:23> 'C *' <LValueToRValue>
        |           `-DeclRefExpr 0x1d33798 <col:23> 'C *' lvalue ParmVar 0x1d33558 'c' 'C *'
        `-CXXMemberCallExpr 0x1d33978 <col:37, col:47> 'int'
          `-MemberExpr 0x1d33930 <col:37, col:43> '<bound member function type>' ->foo 0x1d02400
            `-ImplicitCastExpr 0x1d33998 <col:37> 'A *' <UncheckedDerivedToBase (B -> A)>
              `-ImplicitCastExpr 0x1d33908 <col:37> 'C *' <LValueToRValue>
                `-DeclRefExpr 0x1d338c8 <col:37> 'C *' lvalue ParmVar 0x1d33558 'c' 'C *'

[从此看来,UncheckedDerivedToBase强制转换似乎标记了函数调用非virtual的位置。总是这样吗?我是否应该始终将形式为CXXMemberCallExpr (MemberExpr (ImplicitCastExpr<UncheckedDerivedToBase> e)))的呼叫视为非virtual呼叫?还有其他模式可以指示非virtual函数调用吗?有没有更可靠的方法来确定这一事实?

EDIT:一些进一步的研究表明UncheckedDerivedToBase不足的上述假设。此代码:

struct A {
    virtual int foo() { return 100; }
};
struct B : public A {
    virtual int foo() { return 10; }
};

int test(B* b) {
    return b->foo() + b->B::foo();
}

似乎为两个调用都产生了完全相同的AST节点(至少在控制台上无法区分),但是如果b实际上是派生类,例如,语义应根据标准而有所不同。上面的C

clang clang++ llvm-clang
1个回答
0
投票

区别因素是被叫对象的hasQualifier上的MemberExpr。如果hasQualifiertrue,则函数调用为非virtual

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