JavaScript字符串数组自定义排序

Question

[嗨，我正在尝试在JavaScript中实现自定义字符串比较器功能。我希望某些特殊值始终位于其他值之前，其余的仅按字母顺序排序。例如，如果我有一个数组（“非常重要”和“重要”）是两个特殊值。

    ["e","c","d","Very Important","a",null,"Important","b","Very Important"]. 

排序后，数组应该是（如果存在null或未定义的值，则需要放在最后）

    ["Very Important", "Very Important", "Important", "a","b","c","d","e",null]  

如何为上述要求编写比较器功能？

非常感谢

Answer 1

您可以

• 将null值移到底部，
• 将'Very Important'字符串移到顶部，然后
• 将其余的升序排列。

var array = ["e", "c", "d", "Very Important", "a", null, "Important", "b", "Very Important"];

array.sort((a, b) =>
    (a === null) - (b === null) ||
    (b === 'Very Important') - (a === 'Very Important') ||
    a > b || -(a < b)
);

console.log(...array);

Answer 2

您可以尝试以下操作：

const array = ["e","c","d","Very Important","a",null,"Important","b","Very Important"];
const importantElems = ['Very Important', 'Important'];
const lastElems = [null, undefined];

const firstPart = array.filter(e => importantElems.includes(e));
const middlePart = array.filter(e => !importantElems.includes(e) && !lastElems.includes(e))
                        .sort((a,b) => a.localeCompare(b));
const lastPart = array.filter(e => lastElems.includes(e));

const result = firstPart.concat(middlePart).concat(lastPart);

console.log(result);

我希望有帮助！