将原始 sql 转换为 sql alchemy 没有给出相同的结果

问题描述 投票:0回答:2

我正在尝试将 sql 查询转换为 sqlalchemy 的语法,但我没有得到相同的结果。 sql 查询返回我需要的四个测试行,而 python 只返回两个。我的语法有问题吗?

SQL查询:

SELECT * FROM POW p
    JOIN completed_course cc1 on p.student_id = cc1.student_id
    JOIN term_course tc on cc1.term_course_id = tc.id
    JOIN completed_course cc on tc.id = cc.term_course_id
    LEFT JOIN specialization_course sc on tc.course_id = sc.course_id 
       AND sc.specialization_id = p.specialization_id
    WHERE p.id = 1;

烧瓶 SQLAlchemy:

    def get(self, pow_id):
    try:
        cc = aliased(CompletedCourse)
        cc1 = aliased(CompletedCourse)
        p = aliased(POW)
        tc = aliased(TermCourse)
        sc = aliased(SpecializationCourse)
        results = p.query\
            .join(cc, cc.student_id == p.student_id)\
            .join(tc, tc.id == cc.term_course_id)\
            .join(cc1, cc1.term_course_id == tc.id)\
            .join(sc, and_(sc.course_id == tc.course_id, sc.specialization_id == p.specialization_id), isouter=True)\
            .filter(p.id == pow_id)\
            .all()
        print(results)
        return {}, 200
    except Exception as e:
        raise Exception("")
sql flask flask-sqlalchemy
2个回答
0
投票

如果你想像下面的代码,你可以使用数据库连接:

conn = mysql.connect()
cursor =conn.cursor()

sql_query = """SELECT * FROM POW p
    JOIN completed_course cc1 on p.student_id = cc1.student_id
    JOIN term_course tc on cc1.term_course_id = tc.id
    JOIN completed_course cc on tc.id = cc.term_course_id
    LEFT JOIN specialization_course sc on tc.course_id = sc.course_id 
       AND sc.specialization_id = p.specialization_id
    WHERE p.id = 1;"""

cursor.execute(sql_query)
result = cursor.fetchall()

0
投票

对于 flask_sqlalchemy ,我使用了下面的

sqlText = db.text(original_sql)

db.session.execute(sqlText)

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